TypeError：Attack（）缺少1个必需的位置参数：'self' [英] TypeError: attack() missing 1 required positional argument: 'self'

问题描述

我收到此错误

TypeError: attack() missing 1 required positional argument: 'self'

这是我的代码

class Enemmy :
    life = 3
    self = ""
    def attack(self):
        print ("ouch!!!!")
        self.life -= 1

    def checkLife(self):
        if self.life <= 0 :
            print ("dead")
        else:
            print (self.life)

enemy=Enemmy
enemy.attack()

我检查并查看了大多数地方，说我忘记了在def攻击
中的自我，或者我需要创建一个obj以便将类放入
中，我将python 3.4与py一起使用charm
i实际上是从教程中获得的代码，我不知道我的错误是什么

i checked and looked most places says i forgot the self in the def attack or that i need to make an obj to put the class in im useing python 3.4 with py charm i actually got this code from a tutorial and i dont know what is my mistake

推荐答案

您没有实例化您的 Enemy 类。您正在创建对类本身的新引用。然后，当您尝试调用方法时，您将在没有实例的情况下调用该方法，该实例应该被放入 attack（）<的 self 参数中/ code>。

You're not instantiating your Enemy class. You are creating a new reference to the class itself. Then when you try and call a method, you are calling it without an instance, which is supposed to go into the self parameter of attack().

更改

enemy = Enemy

到

enemy = Enemy()

也（如Kevin在评论中指出的那样）您的 Enemy 类可能应该具有 init 方法来初始化其字段。例如

Also (as pointed out in by Kevin in the comments) your Enemy class should probably have an init method to initialise its fields. E.g.

class Enemy:
    def __init__(self):
        self.life = 3
    ...

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