使用PHP在目录中创建所有类的实例 [英] Create instances of all classes in a directory with PHP

问题描述

我有一个目录，其中包含几个PHP文件，这些文件由与这些文件同名的类组成。 （ Sample.php 的类将称为 Sample 。）

I have a directory with several PHP files consisting of classes with the same names as the files. (Sample.php's class will be called Sample.)

每个此类都有一个名为 OnCall（）的函数。

Each of these classes have a function called OnCall().

如何创建实例目录中每个类的名称并执行其所有 OnCall（） s？

How can I create an instance of every class in my directory and execute all of their OnCall()s?

我无法手动执行（ $ sample = new Sample（）; $ sample-> OnCall（）; 等），因为用户会添加，编辑和删除更多的类。

I cannot do it manually ($sample = new Sample(); $sample->OnCall();, etc etc etc) because more classes will be added, edited and deleted by users.

推荐答案

这样的东西应该会得到完成的工作：

Something like this ought to get the job done:

<?php

    foreach (glob('test/class/*.php') as $file)
    {
        require_once $file;

        // get the file name of the current file without the extension
        // which is essentially the class name
        $class = basename($file, '.php');

        if (class_exists($class))
        {
            $obj = new $class;
            $obj->OnCall();
        }
    }

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