如何将这些装饰函数包装到一个类中? [英] How to wrap these decorated functions into a class?
问题描述
我正在尝试将Slack API的V2包装到一个类中,以便可以封装有关我的机器人的信息。这是他们的示例片段之一:
I am attempting to wrap V2 of the Slack API into a class so that I can keep information about my bot encapsulated. Here is one of their example snippets:
import slack
slack_token = os.environ["SLACK_API_TOKEN"]
rtmclient = slack.RTMClient(token=slack_token)
@slack.RTMClient.run_on(event='message')
def say_hello(**payload):
data = payload['data']
if 'Hello' in data['text']:
channel_id = data['channel']
thread_ts = data['ts']
user = data['user']
webclient = payload['web_client']
webclient.chat_postMessage(
channel=channel_id,
text="Hi <@{}>!".format(user),
thread_ts=thread_ts
)
rtmclient.start()
我的理解是,此 say_hello
函数由于装饰器而被传递到松弛对象中,因此,如果我将其包装到一个类中,则该函数并不是真正位于我的内部类。如何包装 say_hello
函数,使其能够调用属于我的类实例的方法和引用属性?
My understanding here is that this say_hello
function is being passed into the slack object because of the decorator, so if I were to wrap this into a class, that function isn't really sitting inside my class. How do I wrap the say_hello
function for it to be able to call methods and reference properties that belonged to an instance of my class?
推荐答案
看看装饰器的工作原理!
Have a look at how decorators work!
def decorator_factory(f):
def decoration(*args, **kwargs):
print('before')
r = f(*args, **kwargs)
print('after')
return r
return decoration
@decorator_factory
def inc(i):
'''
>>> inc(23)
before
after
42
'''
return i + 1
也许有更好的,规范的方法来实现您想要的目标,但这可以完成工作:
There may be a better, canonical way to achieve what you want, but this would do the job:
class Client():
def __init__(self):
slack.RTMClient.run_on(event='message')(self.decorated)
def decorated(self, x, y, z):
pass
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