调出函数，未定义错误 [英] Calling out a function, not defined error

问题描述

我是上课的新手，我正在尝试完成 Python速成课程这本书中的练习9-1，问题的最后一部分要求我回叫我的方法，但最终还是得到了

I'm new to making classes and I'm trying to complete exercise 9-1 in my 'Python Crash Course' book where the last part of the question asks me to call back my method but I end up getting

describe_restaurant（）的未定义错误。

这是我的代码：

class Restaurant():
    def __init__(self, r_name, c_type):
        self.r_name = r_name
        self.c_type = c_type

    def describe_restaurant():
        print(self.r_name.title())
        print(self.c_type.title())

    def open_restaurant():
        print(self.r_name + " is now open!")

Restaurant = Restaurant('Joe\'s Sushi', 'sushi')

print(Restaurant.r_name)
print(Restaurant.c_type)

describe_restaurant()
open_restaurant()

我认为 describe_restaurant 应该

推荐答案

尝试：

class Restaurant():
    def __init__(self, r_name, c_type):
        self.r_name = r_name
        self.c_type = c_type

    def describe_restaurant(self):
        print(self.r_name)
        print(self.c_type)

    def open_restaurant(self):
        return "{} is now open!".format(self.r_name)

restaurant = Restaurant('Joe\'s Sushi', 'sushi')

print(restaurant.r_name)
print(restaurant.c_type)

restaurant.describe_restaurant()
restaurant.open_restaurant()

您需要创建一个类实例并调用它的函数。另外，如注释中所述，您需要将 self 传递给实例方法。对此的简短说明可以在此处。

You need to create a class instance and call it's functions. In addition, as mentioned in the comments, you need to pass self to the instance methods. A short explanation of this can be found here.

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