复制文件而不重新创建子目录 [英] Copy files without recreating subdirectories

问题描述

我有一个包含约100个子文件夹的目录，这些子文件夹中有近2,000个文件（最多4层）。文件是.txt或.log，每个扩展名都有唯一的文件名。我需要将文件移动或复制（以较快的速度为准）到另一个文件夹的根目录，而不必像xcopy那样重新创建子文件夹结构。这是在Windows xp上

I have a directory that has about 100 subfolders and close to 2,000 files within those subfolders (up to 4 layers). The files are .txt or .log, and each extension has a unique file name. I need to move or copy (whichever is faster) the files to the root of a different folder without recreating the subfolder structure like xcopy does. This is on Windows xp

谢谢。

现有：

Dir1\Folder1\000111.txt
Dir1\Folder2\000112.txt
Dir1\Folder3\000113.log
Dir1\Folder4\Dir2\000114.txt
Dir1\Folder4\Dir2\000115.txt
Dir1\Folder4\Dir2\000116.log
Dir1\Folder5\Dir3\000117.log
Dir1\Folder5\Dir3\000118.txt
Dir1\Folder5\Dir3\Dir4\000119.txt
Dir1\Folder5\Dir3\Dir4\000120.txt
Dir1\Folder5\Dir3\Dir4\000120.log

必需：

Dir9\000111.txt
Dir9\000112.txt
Dir9\000113.log
Dir9\000114.txt
Dir9\000115.txt
Dir9\000116.log
Dir9\000117.log
Dir9\000118.txt
Dir9\000119.txt
Dir9\000120.txt
Dir9\000120.log

推荐答案

怎么样：

for /R %f in (*.txt,*.log) do copy %f dir9\%~nf

以 dir1 发出该问题您的工作目录。

Issue this with dir1 as your working directory.

对/？有的读物？以了解其工作原理。

Have a read of for /? to understand why this works.

当我在中处理语句时，我倾向于像这样首先尝试它们：

When I work on for statements I tend to try them out first like so:

for /R %f in (*.txt,*.log) do @echo copy %f dir9\%~nf

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