在Objective-C中将八进制字符串转换为十进制？ [英] Converting a octal String to Decimal in Objective-C?

问题描述

我试图在Objective-C中进行二进制，八进制，十进制和十六进制之间的转换。
我无法将八进制转换为十进制。

I trying to do conversions between Binary, Octal, Decimal and Hexadecimal in Objective-C. I had problems converting Octal to Decimal.

我尝试了以下操作：

NSString *decString = [NSString stringWithFormat:@"%d", 077];

工作正常，返回预期的63，但是我的八进制值是NSString。我怎么能告诉计算机它是一个八进制；

It works fine, returning 63 as expected, but my Octal value is a NSString. How can I tell the computer that it is a Octal;

我知道有一个叫做 scanHexInt：的方法，我曾经将十六进制转换为十进制，但是似乎没有scanOctInt ...

I know there is a method called "scanHexInt:" which I used to convert Hexadecimal to decimal, but it seems there is no scanOctInt...

任何帮助将不胜感激！

推荐答案

最干净的解决方案可能是：

The cleanest solution is probably:

long result = strtol(input.UTF8String, NULL, 8);

或

long long result = strtoll(input.UTF8String, NULL, 8);

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