偏移UISlider最小值/最大值图像 [英] Offset UISlider Min/Max value images
问题描述
我正在尝试补偿UISlider的最小和最大值图像的x / y位置。
当前,我正在订阅UISlider,并设置最大值图像,如下所示:
I'm trying to offset the x/y position of a UISlider's min and max value images. Currently, I'm sublcassing UISlider and am setting the maximum value image like this:
[self setMaximumValueImage:[UIImage imageNamed:@"circle_with_plus"]];
但是,我需要此图像更接近实际的UISlider,并且对视觉资产的控制很少这个项目。我试过使用
However, I need this image to be closer to the actual UISlider and have little control over visual assets on this project. I've tried using
- (CGRect)maximumValueImageRectForBounds:(CGRect)bounds
不过,我是我的最小/最大值图像可能会动态更改大小,因此我不确定在这种情况下如何正确实现它。是否有其他转移资产的方式?
谢谢
However, I'm my min/max value images may change size dynamically so I'm not sure how to properly implement it in this case. Is there a different way to move the asset? Thanks
推荐答案
否,没有其他方法可以重新定位最小值或最大值的图像。 maximumValueImageRectForBounds:
每次滑块布置其子视图时都会被调用,并且每次更改 maximumValueImage
时,都会布置子视图。 ,这样就足够了:
No, there is no other way to reposition the minimum or maximum value images. maximumValueImageRectForBounds:
gets invoked every time the slider lays out its subviews, and laying out the subviews happens whenever you change the maximumValueImage
, so it is sufficient to do:
@implementation MyCustomSlider
- (CGRect)maximumValueImageRectForBounds:(CGRect)bounds {
CGRect r = [super maximumValueImageRectForBounds:bounds];
r.origin.x -= 3;
return r;
}
@end
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