Itertools产品，无需重复重复 [英] Itertools product without repeating duplicates

问题描述

from itertools import product
teams = ['india', 'australia', 'new zealand']
word_and = ['and']
tmp = '%s %s %s'
items = [teams, word_and, teams]
print(list(tmp % a for a in list(product(*items))))

打印：

['india and india',
 'india and australia',
 'india and new zealand',
 'australia and india',
 'australia and australia',
 'australia and new zealand',
 'new zealand and india',
 'new zealand and australia',
 'new zealand and new zealand']

操作方法：

1. 避免在一个句子中重复使用相同的名称（印度和印度）


2. 仅生成一个组合（印度和澳大利亚或澳大利亚和印度）

http://pythonfiddle.com/product-without -matching-duplicates

推荐答案

您应使用 itertools.combinations 像这样

You should use itertools.combinations like this

>>> from itertools import combinations
>>> teams = ['india', 'australia', 'new zealand']
>>> [" and ".join(items) for items in combinations(teams, r=2)]
['india and australia', 'india and new zealand', 'australia and new zealand']

但是对于这种简单的情况，您可以运行两个循环，像这样

But for this simple case, you can run two loops, like this

>>> ["%s and %s" % (t1, t2) for i, t1 in enumerate(teams) for t2 in teams[i + 1:]]
['india and australia', 'india and new zealand', 'australia and new zealand']

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