尝试对变量列表进行所有操作组合 [英] trying all combinations of operations on list of variables
问题描述
我有一个值列表,例如:
I have a list of values like:
values = [1, 2, 3, 4]
,我想尝试此列表上的所有组合,例如:
and I want to try all combinations on this list like:
1 + 2
1 + 3
1 + 4
1 * 2
1 * 3
1 * 4
1 + 2 * 3
1 + 2 * 4
1 + 3 * 4
等。
以最简洁的方式获得所有这些可能的操作组合的最直接方法是什么?
What would be the most straightforward way to get all these possible combinations of operations in the most succinct way possible?
我想象有两个列表,[1,2,3,4]和[+,*,-,/],然后取所有长度的数字的所有组合,然后填充
I would imagine having two lists, [1,2,3,4] and [+, *, -, /] and then taking all combinations of the numbers of all lengths, and then filling in the blanks with all combinations.
因此选择[1、2、3],然后选择操作的所有排列并将它们组合在一起。这似乎很杂乱,我希望有一种更清晰的方法来编写此代码?
So selecting [1, 2, 3] and then selecting all permutations of the operations and combining them together. This seems messy and I'm hoping there's a clearer way to code this?
推荐答案
这是一个递归解决方案,可从数字和运算符,然后使用 eval
进行计算它:
Here's a recursive solution that builds the expression from numbers & operators and then uses eval
to calculate it:
vals = [1, 2, 3]
operators = ['+', '*', '-', '/']
def expressions(values):
# Base case, only one value left
if len(values) == 1:
yield values
# Iterate over the indexes
for i in range(len(values)):
# Pop value from given index and store the remaining values
# to be used with next recursion
forward = values[:]
val = forward.pop(i)
# Yield all value, operator, subexpression combinations
for op in operators:
for rest in expressions(forward):
yield [val, op] + rest
for expr in expressions(vals):
expr = ' '.join(str(x) for x in expr)
print('{} = {}'.format(expr, eval(expr)))
输出(同等tial):
Output (partial):
1 + 2 + 3 = 6
1 + 2 * 3 = 7
1 + 2 - 3 = 0
1 + 2 / 3 = 1.6666666666666665
1 + 3 + 2 = 6
1 + 3 * 2 = 7
1 + 3 - 2 = 2
1 + 3 / 2 = 2.5
1 * 2 + 3 = 5
1 * 2 * 3 = 6
1 * 2 - 3 = -1
1 * 2 / 3 = 0.6666666666666666
1 * 3 + 2 = 5
1 * 3 * 2 = 6
1 * 3 - 2 = 1
1 * 3 / 2 = 1.5
1 - 2 + 3 = 2
1 - 2 * 3 = -5
1 - 2 - 3 = -4
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