“列表索引超出范围”使用sys.argv [1]时 [英] "list index out of range" when using sys.argv[1]

问题描述

我正在编写一个简单的Python客户端和服务器，可以很好地在代码中传递服务器地址，但是，我希望用户能够输入服务器地址并在错误的情况下抛出错误。当我有下面的代码时，我从终端列表索引超出范围收到错误消息。

I am writing a simple Python client and server, which works fine passing the server address within my code, however, I want the user to be able to enter the server address and throw and error if its incorrect. When I have the code below I get a error message from the terminal "list index out of range".

server = (sys.argv[1])
serverAdd = (server, '65652') # server address and port number

有人可以帮我吗？

当我在python中运行客户端程序时，我希望能够输入一个地址以连接并存储该地址在服务器上。我直接从命令行通过键入programname.py运行该程序。服务器已经开始监听传入的连接。

When I run my client program in python I want to be able to enter a address to connect to and store that in server. I run the program directly from the command line by typing programname.py. The server is already running listening for incoming connections.

推荐答案

使用此Python：

import sys

print(sys.argv)

并使用以下命令调用：

>python q15121717.py 127.0.0.1

我得到以下输出：

['q15121717.py', '127.0.0.1']

我想你没有将参数传递给您的Python脚本

I think you are not passing a argument to your Python script

现在，您可以稍微更改代码以从命令行使用服务器，或者在没有传递参数时提示输入服务器。在这种情况下，您将看到以下内容：

Now you can change your code slightly to take a server form the command line or prompt for a server when none is passed. In this case you would look at something like this:

if len(sys.argv) > 1:
    print(sys.argv[1])
else:
    print(input("Enter address:"))

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