如何从g ++中丢失原型警告？ [英] How do I get missing prototype warnings from g++?

问题描述

我目前有一个使用g ++编译其代码的项目。我正在清理代码，我想确保所有函数都有原型，以确保正确处理const char *之类的东西。不幸的是，当我尝试指定-Wmissing-prototypes时，g ++抱怨：

I currently have a project that uses g++ to compile it's code. I'm in the process of cleaning up the code, and I'd like to ensure that all functions have prototypes, to ensure things like const char * are correctly handled. Unfortunately, g++ complains when I try to specify -Wmissing-prototypes:

g++ -Wmissing-prototypes -Wall -Werror -c foo.cpp
cc1plus: warning: command line option "-Wmissing-prototypes" is valid for Ada/C/ObjC but not for C++

有人可以告诉我：

1）为什么gcc无效？

2）是否可以打开此警告？

Can someone tell me:
1) Why does gcc this isn't valid? Is this a bug in gcc?
2) Is there a way to turn on this warning?

编辑：

这里有一个剪切示例：

cat > foo.cpp <<EOF
void myfunc(int arg1, int arg2)
{
    /* do stuff with arg1, arg2 */
}
EOF
g++ -Wmissing-prototypes -c foo.cpp  # complains about not valid
g++ -c foo.cpp                       # no warnings
# Compile in C mode, warning appears as expected:
g++ -x c -Wmissing-prototypes -c foo.cpp

推荐答案

您尝试-Wmissing-declaration吗？这似乎适用于g ++，并检测您描述的错误情况。我不确定他们将其添加到哪个版本中，但是它在4.3.3中对我有效。

Did you try -Wmissing-declarations? That seems to work for g++ and detect the error case you describe. I'm not sure which version they added it in, but it works for me in 4.3.3.

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