C＃创建具有多个文件的ZIP存档 [英] C# Create ZIP Archive with multiple files

问题描述

我正尝试创建具有多个文本文件的ZIP存档，如下所示：

I'm trying to create a ZIP archive with multiple text files as follows:

Dictionary<string, string> Values = new Dictionary<string, string>();
using (var memoryStream = new MemoryStream())
{
    string zip = @"C:\Temp\ZipFile.zip";
    foreach (var item in Values)
    {
        using (var archive = new ZipArchive(memoryStream, ZipArchiveMode.Create, true))
        {
            var file = archive.CreateEntry(item.Key + ".txt");
            using (var entryStream = file.Open())
            using (var streamWriter = new StreamWriter(entryStream))
            {
                streamWriter.Write(item.Value);
            }
        }
    }
    using (var fileStream = new FileStream(zip, FileMode.Create))
    {
        memoryStream.Seek(0, SeekOrigin.Begin);
        memoryStream.CopyTo(fileStream);
    }
}

但是，只用最后一个文本创建ZIP文件，怎么了？

However, the ZIP is created with only the last text file, what's wrong?

推荐答案

您要在每次迭代中创建 ZipArchive 。交换 foreach 和使用应该可以解决此问题：

You are creating ZipArchive on each iteration. Swapping foreach and using should solve it:

Dictionary<string, string> Values = new Dictionary<string, string>();
using (var memoryStream = new MemoryStream())
{
    string zip = @"C:\Temp\ZipFile.zip";
    using (var archive = new ZipArchive(memoryStream, ZipArchiveMode.Create, true))
    {
        foreach (var item in Values)
        {
            var file = archive.CreateEntry(item.Key + ".txt");
            using (var entryStream = file.Open())
            using (var streamWriter = new StreamWriter(entryStream))
            {
                streamWriter.Write(item.Value);
            }
        }
    }

    using (var fileStream = new FileStream(zip, FileMode.Create))
    {
        memoryStream.Seek(0, SeekOrigin.Begin);
        memoryStream.CopyTo(fileStream);
    }
}

这篇关于C＃创建具有多个文件的ZIP存档的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！