您如何有条件地在“显示”字段中显示字段？反应管理员中的组件？ [英] How do you conditionally show fields in "Show" component in react-admin?

问题描述

我只想显示一些具有值的字段。我希望这样做：

Some fields I want to only show if they have a value. I would expect to do this like so:

<Show {...props} >
  <SimpleShowLayout>
    { props.record.id ? <TextField source="id" />: null }
  </SimpleShowLayout>
</Show>

但这是行不通的。我可以通过使每个字段成为高阶组件来使其有所工作，但我想做一些更简洁的事情。这是我拥有的HOC方法：

But that doesn't work. I can make it somewhat work by making each field a higher order component, but I wanted to do something cleaner. Here's the HOC method I have:

const exists = WrappedComponent => props => props.record[props.source] ?
  <WrappedComponent {...props} />: null;

const ExistsTextField = exists(TextField);

// then in the component:

<Show {...props} >
  <SimpleShowLayout>
    <ExistsTextField source="id" />
  </SimpleShowLayout>
</Show>

这可以正确显示值，但会去除标签。

This correctly shows the value, but strips the label.

推荐答案

我们需要更新有关此内容的文档。同时，您可以在升级指南中找到有关如何实现此目标的信息： https://github.com/marmelab/react-admin/blob/master/UPGRADE.md#aor-dependent-input-was-removed

We need to update our documentation about this. In the mean time, you can find informations about how to achieve that in the upgrade guide: https://github.com/marmelab/react-admin/blob/master/UPGRADE.md#aor-dependent-input-was-removed

下面是一个示例：

import { ShowController, ShowView, SimpleShowLayout, TextField } from 'react-admin';

const UserShow = props => (
    <ShowController {...props}>
        {controllerProps => 
            <ShowView {...props} {...controllerProps}>
                <SimpleShowLayout>
                    <TextField source="username" />
                    {controllerProps.record && controllerProps.record.hasEmail && 
                        <TextField source="email" />
                    }
                </SimpleShowLayout>
            </ShowView>
        }
    </ShowController>
);

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