“％” python给了我“不是在字符串格式化期间转换的所有参数” [英] '%' python is giving me a "not all arguments converted during string formatting"

问题描述

我已经下载了此文本要求我提供的确切版本，但是'％'给了我一个问题。

I've downloaded the exact version this text asked me to however the '%' is giving me a problem.

x = raw_input('Enter an integer:')
if x%2 == 0:
   print ''
   print 'Even'
else:
   print ''
   print 'Odd'
print 'Done with conditional'

只有'％'运算符给我一个问题。任何其他运算符和脚本都可以正常运行。我已经读过该版本很重要，因为％也可以是字符串插值运算符，但是就像我说的那样，我相信我所拥有的版本与我的文本匹配。

It is only the '%' operator giving me a problem. Any other operator and the script runs fine. I've read that the version matters because '%' can also be 'string interpolation operator' but like I said I believe the version I have matches my text. WHAT DO I DO NEXT?

谢谢，是的，我刚刚读了第一本关于编程的书。

Thanks and yes I have pretty much just picked up my first book on programming.

推荐答案

raw_input（） 函数返回字符串，而不是整数。要将其更改为整数，必须调用 int（） 函数：

x = int(raw_input('Enter an integer:'))

请注意，如果输入数字以外的任何内容，都会引发错误。

Note that an error will be raised if you input anything other than a number.

python认为您正在做什么，试图将字符串格式与％运算符。由于您输入的字符串中没有％ ，因此会出现错误并非在格式化字符串时转换了所有参数。

What python thinks you're doing is trying to use string formatting with the % operator. As there are no "%" in the string you input, the error "not all arguments converted during string formatting" is raised.

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