Wordpress的function.php文件中的PHP条件语句不起作用 [英] PHP conditional statements within Wordpress's function.php file not working
问题描述
我想在 function.php
中执行以下PHP语句:如果存在 #header h1 a $ c $的上传图像c>的背景,将文本缩进(删除)...如果没有(否则),保留文本(不缩进)。
I want to do the following PHP statement within function.php
: If there's an uploaded image for #header h1 a
's background, indent the text (remove)...If not (else), keep the text (don't indent it).
我对PHP不太熟悉,但这是我所做的:
I'm not very familiar with PHP but this is what I did:
<?php
// Include functions of Theme Options
require_once(TEMPLATEPATH . '/functions/admin-menu.php');
// If there's an image for the site title, remove it's text
function logo_exists() {
?><style type="text/css">
#header h1 a {
<?php
if ( $options['logo'] == NULL ) { ?>
float: left;
text-indent: 0;
<?php } else { ?>
background: url(<?php echo $options['logo']; ?>) no-repeat scroll 0 0;
float: left;
text-indent: -9999px;
width: 160px;
height: 80px;
}
<?php } ?>
</style><?php
}
header.php:
// Initiate Theme Options
$options = get_option('plugin_options');
var_dump($options['logo'])
?>
<style>
body {
background-color: <?php echo $options['color_scheme']; ?>
}
</style>
</head>
<body <?php body_class(); ?>>
<div id="wrapper">
<div id="header">
<h1>
<a href="<?php echo home_url( '/' ); ?>" title="<?php echo esc_attr( get_bloginfo( 'name', 'display' ) ); ?>" rel="home"><?php bloginfo( 'name' ); ?></a>
</h1>
(我不确定是否有用的信息,但是plugin_options在<$ c之前初始化$ c>< style> 标签。)
(I'm not sure if it is useful information but plugin_options is initialised just before the <style>
tags.)
我做了 var_dump
和 #options ['徽标']
显示:
string(63) "http://localhost/wordpress/wp-content/uploads/2010/12/logo3.png"
(因此图像正常工作)
但是现在我只看到Wordpress网站标题
But right now I just see the Wordpress site title
我必须激活或启动 ** logo_exists 功能吗?
还是有其他问题?**
Do I have to "activate" or "initiate" the function **logo_exists? or is there another problem?**
(如果我不使用PHP If语句并声明$ options,一切正常]直接从header.php中获取)
谢谢!
推荐答案
$ options
在该函数的范围内不存在。您需要添加
$options
doesn't exist in the scope of that function. You need to add
global $options;
紧接在函数声明之后,以便使用 $ options
包含中的变量。像这样:
just after the function declaration, so that it picks up the $options
variable from the include. Like this:
function logo_exists() {
global $options;
?><style type="text/css">
...
这篇关于Wordpress的function.php文件中的PHP条件语句不起作用的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!