怎么称呼静态void Main（string [] args）“再次在类中 [英] how to call " static void Main(string[] args) "in the class again

问题描述

我是C＃的新手，现在有一天我编写了以下代码来处理控制台应用程序：

i am new in C# and working on Console Applications now a days i wrote the following code :

Program.cs

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Threading.Tasks;

namespace Ch06Ex01
{
    class Program
    {
        static void Write()
        {
            Console.WriteLine("Please enter any string..!!");
        }

         static void Main(string[] args)
        {       

            Write();
            string name = Console.ReadLine();
            Write();
            string name1 = Console.ReadLine();
            Write();
            string name2 = Console.ReadLine();
            Write();
            string name3 = Console.ReadLine();

             Console.WriteLine("{0}, {1}, {2}, {3}",name,name1,name2,name3);

             Console.WriteLine("enter \"y\" to restart the program and \"n\" to exit the Program");
             string selectedOption = Console.ReadLine();

             if (selectedOption == "y")
             {
                 // howto call  static void Main(string[] args) here agin so that the program start itself from the start point

             }    

             //else if (selectedOption == "n")
            {
               //Terminate the Program
             }
             Console.ReadKey();
         }      

    }

}

此时的点：

 if (selectedOption == "y")
             {
                 // howto call  static void Main(string[] args) here agin so that the program start itself from the start point

             }    

如果用户输入 y，我想重启程序，如果用户输入 n，我想终止程序，为此，我尝试了所有像这样使用goto语句：

i wanted to reboot the program if User enter "y" and terminate it if the user enter "n", for this purpose firs of all i tried to use goto statement like :

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Threading.Tasks;

namespace Ch06Ex01
{
    class Program
    {
        static void Write()
        {
            Console.WriteLine("Please enter any string..!!");
        }

         static void Main(string[] args)
        {
            StartPoint;

            Write();
            string name = Console.ReadLine();
            Write();
            string name1 = Console.ReadLine();
            Write();
            string name2 = Console.ReadLine();
            Write();
            string name3 = Console.ReadLine();

             Console.WriteLine("{0}, {1}, {2}, {3}",name,name1,name2,name3);

             Console.WriteLine("enter \"y\" to restart the program and \"n\" to exit the Program");
             string selectedOption = Console.ReadLine();

             if (selectedOption == "y")
             {
                 // howto call  static void Main(string[] args) here agin so that the program start itself from the start point
                 goto StartPoint;
             }    

             //else if (selectedOption == "n")
             Console.ReadKey();
         }      

    }
}

但是在 StartPoint上对我不起作用； 会给出错误

Only assignment, call, increment, decrement, await, and new object expressions can be used as a statement   C:\Users\Ahsan\Desktop\C# for Beginners Examples\Ch06Ex01\Ch06Ex01\Program.cs   18  13  Ch06Ex01

然后我尝试在点处调用主函数本身

then i tried to call main function itself at point

 if (selectedOption == "y")
         {
             // howto call  static void Main(string[] args) here agin so that the program start itself from the start point

         }    

但是它给了我这里有很多错误，现在不知道该怎么做，有人可以帮助我吗？不知道该怎么做。...
再次在该类中调用 static void Main（string [] args）……。

but it gives me a lot of error here , don' know how to do it now, can any one help me out ? don't know how to do this thing work.... calling " static void Main(string[] args) "in the class again would be preferred....

推荐答案

只需再次调用该方法，并传递与最初传递的参数相同的参数，也如果可以的话，尽量避免使用goto ：

Just call the method again, passing in the same arguments that where passed in initially, also try to avoid using goto if you can:

if (selectedOption == "y")
{
    // howto call  static void Main(string[] args) here agin so that the program start itself from the start point
    Main(args);
}    

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