如何逃脱“！”当调用angularjs过滤器 [英] How to escape '!' when call angularjs filter

问题描述

AngularJS过滤器保护的一些特殊字符。在predicate可以通过prefixing与！，但现在我想筛选出其中包含的项字符串被否定了'！特殊字符。我怎么能逃脱这个特殊字符'！好吗？

AngularJS filter protected some special chars. The predicate can be negated by prefixing the string with !, but now I want to filter out the items which contains the '!' special char. How can I escapes this special char '!' please?

推荐答案

您不能逃脱它，因为过滤过滤器的没有presume它。

You can't escape it, because filter filter doesn't presume it.

但是你可以使用 predicate功能覆盖默认行为！ predicate和装饰过滤器不破坏任何东西。

But you can use predicate function to override default behaviour for ! predicate and decorate filter without breaking anything else.

app.config(['$provide', function ($provide) {
  function bang(value) {
    return value.indexOf('!') >= 0;
  };

  function bangless(value) {
    return value.indexOf('!') < 0;
  };

  $provide.decorator('filterFilter', ['$delegate', function ($delegate) {
    return function (array, expression, comparator) {
      if (expression === '!') {
        expression = bang;
      } else if (expression === '!!') {
        expression = bangless;
      }

      return $delegate(array, expression, comparator);
    }
  }]);
}]);

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