将Content-Type标头转换为文件扩展名 [英] Convert Content-Type header into file extension

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本文介绍了将Content-Type标头转换为文件扩展名的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

所以我想做的是将HEADER请求内容类型转换为文件扩展名。对于html页面 text / html; charset = utf-8,典型的内容类型是这样的,这是python给出的响应。我一直在研究使用mimetype模块没有成功,因为它看起来无法满足我的需求。



运行时间:



我想将 text / html; charset = utf-8转换为该 .html



典型的图像内容类型取决于图像类型,其为 image / jpeg,但是我对图像不太担心,因为大多数url在路径中指定了图像。



我不想使用基本python库中没有的任何库。



p>

解决方案

您可以拆分并剥离:

  r = requests.get( http://stackoverflow.com/questions/29674905/convert-content-type-header-into-file-extension)

来自mimetypes导入guess_extension

print(guess_extension(r.headers ['content-type']。partition(';')[0] .strip()))
.htm


So what I am trying to do is convert a HEADER requests content-type into a file extension. The typical content-type is like this for html pages "text/html; charset=utf-8" that is the given response from python. I have looked into using the mimetype module with no success as it doesn't look like it accommodates what I am looking for.

Rundown:

I want to convert "text/html; charset=utf-8" into this ".html"

The typical image content-type is "image/jpeg" depending on the image type, but I am not too worried about images, given that most urls specify the image in the path. This is more for websites that don't end in "blahahah.html"

I do not want to use any libraries that are not in the base python library.

解决方案

You could split and strip:

r = requests.get("http://stackoverflow.com/questions/29674905/convert-content-type-header-into-file-extension")

from mimetypes import guess_extension

print(guess_extension(r.headers['content-type'].partition(';')[0].strip()))
.htm

这篇关于将Content-Type标头转换为文件扩展名的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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