如何解决“ NotSerializableException”？在单元测试“ LinearState”的简单实现时抛出 [英] How to resolve a "NotSerializableException" thrown when unit testing a plain implementation of "LinearState"

问题描述

我有一个 LinearState的简单实现，其中唯一的参数是UniqueIdentifier。我有一份简单的合同。

I have a plain implementation of "LinearState" where the only parameter is a UniqueIdentifier. I have a simple Contract to go with it.

但是，当我尝试通过单元测试进行测试时，我会不断收到 NotSerializabeException。

When I try to put it through unit testing, however, I keep getting "NotSerializabeException".

我正在使用Corda v4 Java模板。使用IntelliJ上的Gradle Runner测试设置。

I'm using the Corda v4 java template. Testing setup with Gradle Runner on IntelliJ.

我尝试使用@CordaSerializable注释类，并使用@ConstructorForDeserialization注释构造函数

I've tried annotating the class with @CordaSerializable, and the constructor with @ConstructorForDeserialization

@CordaSerializable
public class InvestorState implements LinearState {

    private final UniqueIdentifier linearId;

    @ConstructorForDeserialization
    public InvestorState(UniqueIdentifier id) {
        this.linearId = id;
    }
...
}

Error log:
data(net.corda.core.contracts.ContractState) -> Trying to build an object serializer for com.mycordapp.states.InvestorState, but it is not constructible from its public properties, and so requires a custom serialiser.

java.io.NotSerializableException: data(net.corda.core.contracts.ContractState) -> Trying to build an object serializer for com.mycordapp.states.InvestorState, but it is not constructible from its public properties, and so requires a custom serialiser.

at net.corda.serialization.internal.amqp.ObjectSerializer$Companion.make(ObjectSerializer.kt:18)
at net.corda.serialization.internal.amqp.DefaultLocalSerializerFactory.makeNonCustomSerializer(LocalSerializerFactory.kt:240)
...

推荐答案

仅需两美分，以备将来参考：
来自Corda文档：

Just my two cents for future reference: From Corda documentation:

建议坚持Corda中的可序列化对象遵循以下规则，因为它们允许对不可变状态对象进行反序列化：

It is recommended that serializable objects in Corda adhere to the following rules, as they allow immutable state objects to be deserialised:

• 构造函数中每个属性的Java Bean getter，名称形式为getX。例如，对于构造函数参数foo，必须有一个名为getFoo（）的getter。

如果foo是布尔值，则可以选择将getter称为isFoo（）（这就是为什么必须使用参数名称编译该类的原因

If foo is a boolean, the getter may optionally be called isFoo() (this is why the class must be compiled with parameter names turned on)

• 一个构造函数，它采用您希望以序列化形式记录的所有属性。

这是序列化框架重建类实例的必需条件。

This is required in order for the serialization framework to reconstruct an instance of your class.

如果提供了多个构造函数，则序列化框架需要知道要使用哪个构造函数。 @ ConstructorForDeserialization 注释可用于指示哪个。

If more than one constructor is provided, the serialization framework needs to know which one to use. The @ConstructorForDeserialization annotation can be used to indicate which one.

对于Kotlin类，如果没有@ConstructorForDeserialization批注，将选择主构造函数。

For a Kotlin class, without the @ConstructorForDeserialization annotation, the primary constructor will be selected.

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