Java中的减量和赋值运算符 [英] Decrement and assignment operator in java

问题描述

有人可以解释为什么下面的代码输出为1。

Can somebody explain why output of the code below is 1.

int i = 1;
i=i--;
System.out.println(i); // 1

推荐答案

i- -执行以下步骤：

• 返回 i


• 递减 i 1

• return the value of i
• decrement i by 1

所以语句 i = i-执行以下操作：

so the statement i = i-- does the following:

• i 返回（语句现在等于 i = 1 ）


• i 递减（i现在为0）


• 语句（赋值）现在已完成（ i = 1 ）

• i is returned (the statement now equals i = 1)
• i is decremented (i is now 0)
• the statement (the assignment) is now done (i = 1)

最后 i 是1

为了更清楚一点，您可以说 i = i- -; 与以下代码几乎相同：

To make it a bit more clear you could say the line i = i--; does pretty much the same as this code:

int j = i;
i = i-1;
i = j;

这篇关于Java中的减量和赋值运算符的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！