计算向量中不同值的数量 [英] Count number of distinct values in a vector

问题描述

我想得到一个标量值向量：有多少个不同的值。

I have a vector of scalar values of which I'm trying to get: "How many different values there are".

例如 group<-c（1,2,3,1,2,3,4,6）的唯一值是 1,2,3,4,6 ，所以我想得到 5 。

For instance in group <- c(1,2,3,1,2,3,4,6) unique values are 1,2,3,4,6 so I want to get 5.

我想出了：

length(unique(group))

但是我不确定这是最有效的方法。

But I'm not sure it's the most efficient way to do it. Isn't there a better way to do this?

注意：我的情况比示例更复杂，由大约1000个数字组成最多25个不同的值。

Note: My case is more complex than the example, consisting of around 1000 numbers with at most 25 different values.

推荐答案

以下是一些想法，指向您解决方案的所有观点已经非常快。 length（unique（x））也是我会用的：

Here are a few ideas, all points towards your solution already being very fast. length(unique(x)) is what I would have used as well:

x <- sample.int(25, 1000, TRUE)

library(microbenchmark)
microbenchmark(length(unique(x)),
               nlevels(factor(x)),
               length(table(x)),
               sum(!duplicated(x)))
# Unit: microseconds
#                 expr     min       lq   median       uq      max neval
#    length(unique(x))  24.810  25.9005  27.1350  28.8605   48.854   100
#   nlevels(factor(x)) 367.646 371.6185 380.2025 411.8625 1347.343   100
#     length(table(x)) 505.035 511.3080 530.9490 575.0880 1685.454   100
#  sum(!duplicated(x))  24.030  25.7955  27.4275  30.0295   70.446   100

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