批量计算文本文件的行数，不留空白 [英] Batch counting number of lines of text file without blank

问题描述

我有两个格式不同的文本文件，可以说我已经知道文件中有4个非空行，如下所示（第1个有效，第2个无效）。

I got two text files with different formats,let says i already have known there are 4 non-empty lines in the file,shown below (1st is valid, 2nd is invalid).

AAA

BBB

CCC

END

（空白行）

（空行）

AAA

BBB

（空白行）

CCC

END

任何 for循环实现/区分第一个文件的方式都有4个非空行，可以分辨出它是有效的还是第二个文件

Any "for loop" implementations/ways to distinguish 1st file has 4 non-empty lines which can tell it's valid and 2nd file has a extra blank line in the middle which can tell it's invalid.

因为中间有一个多余的空行，可以表明它是无效的。因为我有一个for循环代码，可以计算非空行号，因此将该代码应用于此2个文件，它给我行号= 4，我不想要它，因为第二个文件格式无效。
我的for循环代码

Because i got a for loop code which can count non-empty line number,applying that code in this 2 files,it gives me line number=4,which i don't want it cause 2nd file is invalid format. my for-loop code

        set count=0
        for /f %%a in (%text_file%) do set /a count+=1
        echo %count%

任何建议使用行计数方法识别两个文件？

Any suggestion to identify two files by using lines-counting method?

或者您可以告诉我如何计算从开始到关键字符串 END之间的行数，谢谢。^

Or you can tell me how to count the number of lines from starting until the critical string "END",Thanks in advance^.^

推荐答案

for /f "tokens=1 delims=:" %%i in ('findstr /n "^END$" %text_file%') do set endline=%%i
echo %endline%

这会找到（最后）行的行号，该行号等于< StartOfLine> END< EndOfLine>

this finds the linenumber of the (last) line, that is equal to <StartOfLine>END<EndOfLine>

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