是否有一个内置的方式来获得无任何查询参数当前的URL？ [英] Is there a built-in way to get the current URL without any query parameters?

问题描述

如果我的网址 http://www.something.com/foo/bar/index.html?color=yellow&animal=rat ，它好像

• $ location.path（）将返回富/酒吧/ index.html的


• $ location.absUrl（）将返回 http://www.something.com/foo/bar/index.html?color=黄色和放大器;动物=鼠


• $ location.url（）将返回富/酒吧/ index.html的颜色=黄色和放大器;动物大鼠=

• $location.path() will return foo/bar/index.html
• $location.absUrl() will return http://www.something.com/foo/bar/index.html?color=yellow&animal=rat
• $location.url() will return foo/bar/index.html?color=yellow&animal=rat

有没有这将返回任何功能 http://www.something.com/foo/bar/index.html ？

Is there any function which will return http://www.something.com/foo/bar/index.html?

还是我必须要构建自己像协议型，主机，端口等功能（或剥离查询参数过我自己）？

Or do I have to construct that myself with functions like protcol, host, port, etc. (or strip the query params off myself)?

推荐答案

据我所知，你必须自己建立它。这并不是说你问如何构建它，但对于那些谁是纳闷：

As far as I'm aware you have to construct it yourself. Not that you were asking how to construct it, but for those who are wondering:

var url = $location.absUrl().split('?')[0]

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