CSS3 flexbox布局在一行上最多3个子项 [英] CSS3 flexbox layout max 3 child items on one line
问题描述
在将下一个子元素推到新行之前,它们是否是CSS中在同一行上具有固定最大子项数量的简单方法?
Is their an simple way in CSS to have a fixed maximum of child items on the same line, before you push the next child elements to a new line?
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据我了解flexbox,如果子项在其上方的行上没有足够的可用空间,则仅将其推到新行。但是我正在寻找一个CSS规则或函数,让我说 我希望在任何给定行上最多包含3个子项,即使第4个位置有可用空间,也要将其推入新的行 。
As i understand flexbox, child items only get pushed to a new line if their isint enough available space on the line above it. But i am seeking a CSS rule or function that let me say "i want a maximum of 3 child items on any given line, and even if space is available for a 4'th one push it to a new line".
推荐答案
除了使用display:flex之外,您还可以使用float:left和clear每个第3个子节点,如下所示:
Instead of using display: flex you could use float: left and clear every 3rd child node like this:
.child {
background: #000;
height: 300px;
float: left;
margin:15px 0 0 15px;
width:150px;
}
.child:nth-child(3n+1) {
clear: left;
}
我为您创建了一个小提琴:小提琴示例
I created a fiddle for you: fiddle example
在父母只能容纳两个孩子的情况下,您可以使用此简短的jQuery修复:
In the case that the parent can hold only two children, you could use this short jQuery fix:
var child = $('.child'),
parent = $('.child').parent();
if( child.width() > (parent.width()/3) ) {
child.css('clear', 'none');
}
修正为小提琴:提琴示例2
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