如何在python中发出发布请求 [英] how to make post request in python
本文介绍了如何在python中发出发布请求的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
这是curl命令:
curl -H "X-API-TOKEN: <API-TOKEN>" 'http://foo.com/foo/bar' --data #
让我解释一下进入数据
POST /foo/bar
Input (request JSON body)
Name Type
title string
body string
因此,基于此。我想通了:
So, based on this.. I figured:
curl -H X-API-TOKEN:' http://foo.com/foo/bar '--data'{ title: foobar, body:此主体同时具有双引号和单引号 }'
curl -H "X-API-TOKEN: " 'http://foo.com/foo/bar' --data '{"title":"foobar","body": "This body has both "double" and 'single' quotes"}'
不幸的是,我也无法弄清楚(例如cli的curl)
尽管我想使用python来发送此请求。
我该怎么做?
Unfortunately, I am not able to figure that out as well (like curl from cli) Though I would like to use python to send this request. How do i do this?
推荐答案
使用标准Python httplib
和 urllib
库可以执行
With the standard Python httplib
and urllib
libraries you can do
import httplib, urllib
headers = {'X-API-TOKEN': 'your_token_here'}
payload = "'title'='value1'&'name'='value2'"
conn = httplib.HTTPConnection("heise.de")
conn.request("POST", "", payload, headers)
response = conn.getresponse()
print response
或者如果您想使用名为请求 。
or if you want to use the nice HTTP library called "Requests".
import requests
headers = {'X-API-TOKEN': 'your_token_here'}
payload = {'title': 'value1', 'name': 'value2'}
r = requests.post("http://foo.com/foo/bar", data=payload, headers=headers)
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