如何在Python中启动后台进程？ [英] How to start a background process in Python?

问题描述

我正在尝试将Shell脚本移植到可读性更高的python版本。原始的shell脚本在后台使用&启动多个进程（实用程序，监视器等）。如何在python中达到相同的效果？我希望这些过程在Python脚本完成后不会消失。我确定它某种程度上与守护程序的概念有关，但是我找不到如何轻松实现此目的。

I'm trying to port a shell script to the much more readable python version. The original shell script starts several processes (utilities, monitors, etc.) in the background with "&". How can I achieve the same effect in python? I'd like these processes not to die when the python scripts complete. I am sure it's related to the concept of a daemon somehow, but I couldn't find how to do this easily.

推荐答案

注意：此答案的发布时间比2009年发布时要少。现在建议使用其他答案中显示的子流程模块在文档中

Note: This answer is less current than it was when posted in 2009. Using the subprocess module shown in other answers is now recommended in the docs

（请注意，子流程模块提供了更强大的工具来生成新流程并检索其结果；使用该模块胜于使用这些功能。）

(Note that the subprocess module provides more powerful facilities for spawning new processes and retrieving their results; using that module is preferable to using these functions.)

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如果想让进程在后台启动，则可以使用 system（）并以与您的Shell脚本相同的方式调用它，或者您可以生成它：

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If you want your process to start in the background you can either use system() and call it in the same way your shell script did, or you can spawn it:

import os
os.spawnl(os.P_DETACH, 'some_long_running_command')

（或者，您也可以尝试使用不太便携的 os.P_NOWAIT 标志）。

(or, alternatively, you may try the less portable os.P_NOWAIT flag).

请参见此处的文档。

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