Dartlang等待不止一个未来 [英] Dartlang wait more than one future

问题描述

我想在以后的很多功能完成后做些事情，但是我不知道如何用dart编写代码？
像这样的代码：

I want to do something after a lot of future function done,bu I do not know how to write the code in dart? the code like this:

for (var d in data) {
  d.loadData().then()
}
// when all loaded
// do something here

但我不想一一等待它们：

but I don't want to wait them one by one:

for (var d in data) {
  await d.loadData(); // NOT NEED THIS
}

如何用dart编写这些代码？

how to write those code in dart?

推荐答案

您可以使用 Future.wait 等待期货列表：

You can use Future.wait to wait for a list of futures:

import 'dart:async';

Future main() async {
  var data = [];
  var futures = <Future>[];
  for (var d in data) {
    futures.add(d.loadData());
  }
  await Future.wait(futures);
}

DartPad示例

这篇关于Dartlang等待不止一个未来的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！