Flutter：测试是否抛出特定异常 [英] Flutter: Test that a specific exception is thrown

问题描述

简而言之， throwsA（任何东西）对我来说在飞镖单元测试中是不够的。我如何测试特定的错误消息或类型？

这是我想捕获的错误：

 类MyCustErr实现了异常{
字符串条件； 
 
字符串errMsg（）=> ’您已经添加了一个ID为
 $ term的容器。不允许重复’； 
 
 MyCustErr（{this.term}）; 
} 
  

这是当前通过的断言，但想检查错误上面的类型：

expect（（）=> operation.lookupOrderDetails（），throwsA（anything））;

这就是我想做的：

expect（（）=> ; Operations.lookupOrderDetails（），throwsA（MyCustErr））;

解决方案

想要：

  expect（（）=> operations.lookupOrderDetails（），throwsA（const TypeMatcher< MyCustErr>（））） ; 
 
 Expect（（）=> Operations.lookupOrderDetails（），isInstanceOf< MyCustErr>（））; 
  

如果您只想检查异常，请检查此答案：

in short, throwsA(anything) does not suffice for me while unit testing in dart. How to I test for a specific error message or type?

Here is the error I would like to catch:

class MyCustErr implements Exception {
  String term;

  String errMsg() => 'You have already added a container with the id 
  $term. Duplicates are not allowed';

  MyCustErr({this.term});
}

here is the current assertion that passes, but would like to check for the error type above:

expect(() => operations.lookupOrderDetails(), throwsA(anything));

This is what I want to do:

expect(() => operations.lookupOrderDetails(), throwsA(MyCustErr));

解决方案

This should do what you want:

expect(() => operations.lookupOrderDetails(), throwsA(const TypeMatcher<MyCustErr>()));

expect(() => operations.lookupOrderDetails(), isInstanceOf<MyCustErr>());

if you just want to check for exception check this answer:

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