减去日期以获得天数 [英] Subtract dates to get the number of days

问题描述

我正在尝试编写一个php代码，它将能够减去两个日期并获得两个日期之间的天数。我想出的代码如下

I am trying to write a php code which will be able to subtract two dates and get the number of days between the two dates. The code I came up with is given below

<?php
$c_date = date("Y-m-d");
//Subtracting two dates.
$date1 = new DateTime($d_date); //$d_date gets its value from database which i havent shown here
$date2 = new DateTime($c_date);
$interval = $date1->diff($date2);
echo "difference " . $interval->y . " years, " . $interval->m." months, ".$interval->d." days ";
?>

现在上面的代码有效，但是我无法使用它来满足我的需要。我需要能够确定交货日期（$ d_date）是否在当前日期之后的5天内，如果是这种情况，则返回值1。

Now the above code works but I am not able to use it to suit my needs. I need to be able to find out if the delivery date ($d_date) is within 5 days from the current date and return value 1 if that is that case.

因此，如果 $ c_date = 2013-09-24 和 $ d_date = 2013-09-30 然后我将返回1。
但是麻烦的是，当说交货日期是 2013-09-19时交货日期已经很久了，我应该返回0，但是用当前代码，天的差仍然是5，所以我将返回1，这是错误的。

So if $c_date = "2013-09-24" and $d_date = "2013-09-30" then I will be returning 1. But the trouble is when say the delivery date is "2013-09-19" the delivery date has long past and I should be returning 0, but with the current code the difference in day would still be 5 and so i will be returning 1 which is wrong.

对如何克服这个问题有任何想法吗？

Have any ideas as to how to overcome this?

推荐答案

好的，这就是Maximus2012所建议的必需代码，首先使用if语句比较日期。所以这是代码

Ok so here is the required code, as Maximus2012 suggested, using a if statement to compare the dates first did the work. So here is the code

$date1 = new DateTime($ddate[$counter]);
                $date2 = new DateTime($c_date);
                if($date2>$date1)
                {
                    $stat = 0;
                }
$interval = $date1->diff($date2);
                $d_diff = $interval->d;
if($d_diff>5)
{
$stat = 0;
}

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