SQL DateDiff高级用法? [英] SQL DateDiff advanced usage?
问题描述
我需要计算两个日期之间的DateDiff(小时),但仅在工作时间(8:30-16:00,无周末)期间计算。然后,将根据以下示例将结果放入 Reaction_Time列。
I need to calculate the DateDiff (hours) between two dates, but only during business-hours (8:30 - 16:00, no weekends). This result will then be put into the Reaction_Time column as per the example below.
ID Date Reaction_Time Overdue
1 29.04.2003 15:00:00
1 30.04.2003 11:00:00 3:30
2 30.04.2003 14:00:00
2 01.05.2003 14:00:00 7:30 YES
*注意:我没有检查示例中的日期是否是假期。
*Note: I didn't check to see if the dates in example were holidays.
我正在使用SQL Server 2005
I'm using SQL Server 2005
这将与更大的查询结合使用,但是现在我需要的只是这个入门会尝试弄清楚如何将所有内容单独放置在一起。谢谢您的帮助!
This will be combined with a bigger query, but for now all I need is this to get started, I'll try to figure out how to put it all together on my own. Thanks for the help!
编辑:谢谢大家的答复。但由于SQL方面解决方案的明显复杂性,因此决定我们将在Excel中执行此操作,因为无论如何该位置都将移动报表。很抱歉给您带来麻烦,但是我真的觉得比这要简单得多。照原样,我们只是没有时间。
Hey, thanks everyone for the replies. But due to the obvious complexity of a solution on SQL side, it was decided we would do this in Excel instead as that's where the report will be moved anyway. Sorry for the trouble, but I really figured it would be simpler than this. As it is, we just don't have the time.
推荐答案
DECLARE @BusHourStart DATETIME, @BusHourEnd DATETIME
SELECT @BusHourStart = '08:30:00', @BusHourEnd = '16:00:00'
DECLARE @BusMinutesStart INT, @BusMinutesEnd INT
SELECT @BusMinutesStart = DATEPART(minute,@BusHourStart)+DATEPART(hour,@BusHourStart)*60,
@BusMinutesEnd = DATEPART(minute,@BusHourEnd)+DATEPART(hour,@BusHourEnd)*60
DECLARE @Dates2 TABLE (ID INT, DateStart DATETIME, DateEnd DATETIME)
INSERT INTO @Dates2
SELECT 1, '15:00:00 04/29/2003', '11:00:00 04/30/2003' UNION
SELECT 2, '14:00:00 04/30/2003', '14:00:00 05/01/2003' UNION
SELECT 3, '14:00:00 05/02/2003', '14:00:00 05/06/2003' UNION
SELECT 4, '14:00:00 05/02/2003', '14:00:00 05/04/2003' UNION
SELECT 5, '07:00:00 05/02/2003', '14:00:00 05/02/2003' UNION
SELECT 6, '14:00:00 05/02/2003', '23:00:00 05/02/2003' UNION
SELECT 7, '07:00:00 05/02/2003', '08:00:00 05/02/2003' UNION
SELECT 8, '22:00:00 05/02/2003', '23:00:00 05/03/2003' UNION
SELECT 9, '08:00:00 05/03/2003', '23:00:00 05/04/2003' UNION
SELECT 10, '07:00:00 05/02/2003', '23:00:00 05/02/2003'
-- SET DATEFIRST to U.S. English default value of 7.
SET DATEFIRST 7
SELECT ID, DateStart, DateEnd, CONVERT(VARCHAR, Minutes/60) +':'+ CONVERT(VARCHAR, Minutes % 60) AS ReactionTime
FROM (
SELECT ID, DateStart, DateEnd, Overtime,
CASE
WHEN DayDiff = 0 THEN
CASE
WHEN (MinutesEnd - MinutesStart - Overtime) > 0 THEN (MinutesEnd - MinutesStart - Overtime)
ELSE 0
END
WHEN DayDiff > 0 THEN
CASE
WHEN (StartPart + EndPart - Overtime) > 0 THEN (StartPart + EndPart - Overtime)
ELSE 0
END + DayPart
ELSE 0
END AS Minutes
FROM(
SELECT ID, DateStart, DateEnd, DayDiff, MinutesStart, MinutesEnd,
CASE WHEN(@BusMinutesStart - MinutesStart) > 0 THEN (@BusMinutesStart - MinutesStart) ELSE 0 END +
CASE WHEN(MinutesEnd - @BusMinutesEnd) > 0 THEN (MinutesEnd - @BusMinutesEnd) ELSE 0 END AS Overtime,
CASE WHEN(@BusMinutesEnd - MinutesStart) > 0 THEN (@BusMinutesEnd - MinutesStart) ELSE 0 END AS StartPart,
CASE WHEN(MinutesEnd - @BusMinutesStart) > 0 THEN (MinutesEnd - @BusMinutesStart) ELSE 0 END AS EndPart,
CASE WHEN DayDiff > 1 THEN (@BusMinutesEnd - @BusMinutesStart)*(DayDiff - 1) ELSE 0 END AS DayPart
FROM (
SELECT DATEDIFF(d,DateStart, DateEnd) AS DayDiff, ID, DateStart, DateEnd,
DATEPART(minute,DateStart)+DATEPART(hour,DateStart)*60 AS MinutesStart,
DATEPART(minute,DateEnd)+DATEPART(hour,DateEnd)*60 AS MinutesEnd
FROM (
SELECT ID,
CASE
WHEN DATEPART(dw, DateStart) = 7
THEN DATEADD(SECOND, 1, DATEADD(DAY, DATEDIFF(DAY, 0, DateStart), 2))
WHEN DATEPART(dw, DateStart) = 1
THEN DATEADD(SECOND, 1, DATEADD(DAY, DATEDIFF(DAY, 0, DateStart), 1))
ELSE DateStart END AS DateStart,
CASE
WHEN DATEPART(dw, DateEnd) = 7
THEN DATEADD(SECOND, -1, DATEADD(DAY, DATEDIFF(DAY, 0, DateEnd), 0))
WHEN DATEPART(dw, DateEnd) = 1
THEN DATEADD(SECOND, -1, DATEADD(DAY, DATEDIFF(DAY, 0, DateEnd), -1))
ELSE DateEnd END AS DateEnd FROM @Dates2
)Weekends
)InMinutes
)Overtime
)Calculation
这篇关于SQL DateDiff高级用法?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!