如何将ISO 8601日期时间字符串转换为Python日期时间对象？ [英] How do I translate an ISO 8601 datetime string into a Python datetime object?

问题描述

我正在获取日期时间字符串，其格式为 2009-05-28T16：15：00（我相信这是ISO 8601）。一种可能的选择似乎是使用 time.strptime 解析字符串，并将元组的前六个元素传递到datetime构造函数中，例如：

I'm getting a datetime string in a format like "2009-05-28T16:15:00" (this is ISO 8601, I believe). One hackish option seems to be to parse the string using time.strptime and passing the first six elements of the tuple into the datetime constructor, like:

datetime.datetime(*time.strptime("2007-03-04T21:08:12", "%Y-%m-%dT%H:%M:%S")[:6])

我找不到一个清洁的方式。

I haven't been able to find a "cleaner" way of doing this. Is there one?

推荐答案

我更喜欢使用 dateutil 库，用于时区处理和一般可靠的日期解析。如果要获得 ISO 8601 字符串，例如： 2010-05-08T23：41：54.000Z 使用strptime解析时会很有趣，尤其是如果您不预先知道是否包含时区的时候。 pyiso8601 在使用过程中遇到了一些问题（请检查其跟踪器），并且几年没有更新。相比之下，dateutil一直很活跃并为我工作：

I prefer using the dateutil library for timezone handling and generally solid date parsing. If you were to get an ISO 8601 string like: 2010-05-08T23:41:54.000Z you'd have a fun time parsing that with strptime, especially if you didn't know up front whether or not the timezone was included. pyiso8601 has a couple of issues (check their tracker) that I ran into during my usage and it hasn't been updated in a few years. dateutil, by contrast, has been active and worked for me:

import dateutil.parser
yourdate = dateutil.parser.parse(datestring)

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