如何在C ++中将格式化的字符串HH：MM：SS转换为秒 [英] How to convert formatted string HH:MM:SS to seconds in C++

问题描述

我想将以HH：MM：SS格式格式化的字符串时间戳记仅转换为秒，然后将其与数字进行比较。我已经用Java编写了我的代码的主要版本，但是我单独向Scanner询问，而不是花费 string 时间。我对Java ++不太熟悉。想知道如何用C ++做到吗？

I want to convert a string time stamp formatted in HH:MM:SS to seconds only, and then compare it with a number. I have written a prime version of my code in Java, however I separately ask from Scanner as opposed to having a string time. I'm not much familiar with C++ libraries, as I'm a Java guy. Wondering how I can do it in C++?

简单点说， String s = 1:01:01; 和字符串s2 = 3600; 我需要知道 if（s> s2）

Make it brief, String s = "1:01:01"; and String s2= "3600"; I need to know if (s>s2)

import java.util.*;

public class Test {
    public static void main(String[] args) {
        Scanner console = new Scanner(System.in);

        int hours;
        int mins;
        int secs;

        System.out.println("Enter Hours: ");
        hours = console.nextInt();

        System.out.println("Enter Minutes: ");
        mins = console.nextInt();

        System.out.println("Enter Seconds: ");
        secs = console.nextInt();

        int showSecs = (hours * 3600) + (mins * 60) + secs;

        System.out.println(hours + ":" + mins + ":" + secs + " in secs are "
                + showSecs);

    }
}

推荐答案

我将冒风险投票并提醒您，我们的工具箱中仍然有 sscanf 。

I'll risk the downvotes and remind you that we still have sscanf in our toolbox.

int h, m, s= 0;
std::string time ="10:40:03"

if (sscanf(time.c_str(), "%d:%d:%d", &h, &m, &s) >= 2)
{
  int secs = h *3600 + m*60 + s;
}

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