Python计算时差，以1表示“年，月，日，小时，分钟和秒” [英] Python calculating time difference, to give ‘years, months, days, hours, minutes and seconds’ in 1

问题描述

我想知道在'2014-05-06 12:00:56'和'2012-03-06 16:08:22'之间的年，月，日，小时，分钟和秒。结果应类似于：差异为xxx年xxx月xxx天xxx小时xxx分钟

I want to know how many years, months, days, hours, minutes and seconds in between '2014-05-06 12:00:56' and '2012-03-06 16:08:22'. The result shall looked like: "the difference is xxx year xxx month xxx days xxx hours xxx minutes"

例如：

import datetime

a = '2014-05-06 12:00:56'
b = '2013-03-06 16:08:22'

start = datetime.datetime.strptime(a, '%Y-%m-%d %H:%M:%S')
ends = datetime.datetime.strptime(b, '%Y-%m-%d %H:%M:%S')

diff = start – ends

如果我这样做：

diff.days

以天为单位给出差值。

It gives the difference in days.

我还能做什么？以及如何获得所需的结果？

What else I can do? And how can I achieve the wanted result?

推荐答案

使用 relativedelta 来自 dateutil软件包。

import datetime
from dateutil.relativedelta import relativedelta

a = '2014-05-06 12:00:56'
b = '2013-03-06 16:08:22'

start = datetime.datetime.strptime(a, '%Y-%m-%d %H:%M:%S')
ends = datetime.datetime.strptime(b, '%Y-%m-%d %H:%M:%S')

diff = relativedelta(start, ends)

>>> print "The difference is %d year %d month %d days %d hours %d minutes" % (diff.years, diff.months, diff.days, diff.hours, diff.minutes)
The difference is 1 year 1 month 29 days 19 hours 52 minutes

您可能想要添加一些逻辑来打印，例如 2年而不是 2年。

You might want to add some logic to print for e.g. "2 years" instead of "2 year".

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