使用boost.serialization序列化本征矩阵 [英] serializing Eigen's Matrix using boost.serialization

问题描述

我正在尝试序列化本征矩阵。这样我就可以序列化一个更复杂的对象。
我使用Matrix作为基类，并将序列化包含在派生类中。我对如何处理Matrix.data（）感到困惑，该方法会返回C样式的数组（如果我正确的话）。
这是我的尝试：

I'm trying to serialize Eigen's matrix. So that I can serialize a more complex object. I'm using Matrix as a base class and include the serialization in the derived class. I'm confused on how to address Matrix.data(), which returns a c-style array (if i'm correct). This is my attempt:

#include <boost/archive/text_oarchive.hpp>
#include <boost/archive/text_iarchive.hpp>

template < class TEigenMatrix>
class VariableType : public TEigenMatrix {
private:
  friend class boost::serialization::access;
  template<class Archive>
  void serialize(Archive & ar, const unsigned int version)
  {
      ar & this.data();
  }
public:
};

我想将其用作包装纸：

VariableType<Matrix<double,3,1>> serializableVector;

代替

Matrix<double,3,1> vector;

推荐答案

通过将以下免费函数放入编译单元，您可以有效地使Boost.Serialization知道如何序列化本征类型：

By placing the following free function into your compilation unit, you effectively make Boost.Serialization aware of how to serialize Eigen types:

namespace boost
{
    template<class Archive, typename _Scalar, int _Rows, int _Cols, int _Options, int _MaxRows, int _MaxCols>
    inline void serialize(
        Archive & ar, 
        Matrix<_Scalar, _Rows, _Cols, _Options, _MaxRows, _MaxCols> & t, 
        const unsigned int file_version
    ) 
    {
        for(size_t i=0; i<t.size(); i++)
            ar & t.data()[i];
    }
}

在您给出的示例中，您应该能够要做（未试用）：

In the example you gave, you should then be able to do (untested):

void serialize(Archive & ar, const unsigned int version)
{
    ar & *this;
}

看看我的先前的答案有关使用Boost.Serialization对本征类型进行序列化的详细示例。

Have a look at my previous answer on serialization of Eigen types using Boost.Serialization for a more detailed example.

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