如何在Android中获取真实的设备模型？ [英] How to get real device model in Android?

问题描述

例如，在我的Xperia迷你手机上，

For example, on my Xperia mini phone,

• Build.MODEL 返回'st15i'


• Build.MANUFACTURER 返回索尼爱立信

• Build.MODEL returns 'st15i'
• Build.MANUFACTURER returns 'Sony Ericsson'

，但我想为此手机获得'Sony Ericsson xperia mini'。

but I want to get 'Sony Ericsson xperia mini' for this phone.

有可能吗？

推荐答案

针对该特定手机（也许还有许多其他索尼爱立信手机）您只能通过读取您提到的系统属性来获得真实的设备名称： ro.semc.product.model

For that particular phone (and perhaps for many others SonyEricsson phones) you can get the real device name only by reading system property you have mentioned: ro.semc.product.model

由于 android.os.SystemProperties 类已从公共API中隐藏，因此您需要使用反射（或exec getprop ro.semc.product.model 命令和获取其输出）：

Since android.os.SystemProperties class is hidden from public API you will need to use a reflection (or exec getprop ro.semc.product.model command and grab its output):

public String getSonyEricssonDeviceName() {
  String model = getSystemProperty("ro.semc.product.model");
  return (model == null) ? "" : model;
}


private String getSystemProperty(String propName) {
  Class<?> clsSystemProperties = tryClassForName("android.os.SystemProperties");
  Method mtdGet = tryGetMethod(clsSystemProperties, "get", String.class);
  return tryInvoke(mtdGet, null, propName);
}

private Class<?> tryClassForName(String className) {
  try {
    return Class.forName(className);
  } catch (ClassNotFoundException e) {
    return null;
  }
}

private Method tryGetMethod(Class<?> cls, String name, Class<?>... parameterTypes) {
  try {
    return cls.getDeclaredMethod(name, parameterTypes);
  } catch (Exception e) {
    return null;
  }
}

@SuppressWarnings("unchecked")
private <T> T tryInvoke(Method m, Object object, Object... args) {
  try {
    return (T) m.invoke(object, args);
  } catch (InvocationTargetException e) {
    throw new RuntimeException(e);
  } catch (Exception e) {
    return null;
  }
}

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