如何在Swift iOS中顺序访问Dictionary项目？ [英] How to access Dictionary items sequentially in Swift iOS?

问题描述

是否可以按顺序访问字典中的项目。我知道字典主要用于随机访问。当我尝试访问作为键值对时，我的订单更改为名称，id，标题等...

Is it possible to access the items sequentially on the dictionary. I know that dictionary mainly intended for random access. When I am trying to access as key value pairs, my order changes to name, id, header,...etc

let inputDataSet = ["id":1, "name":"Thomas", "role":"Programming Geek", "header":"bla", "dept":"nloo", "address":"dsd", "pic":"asd"

for (key,value) in inputDataSet {
      print("current key:\(key) value:\(value as! String)")
}

推荐答案

最适合您的选择这将是 KeyValuePairs

The best option for you here would be KeyValuePairs

键值对的轻量级集合。

A lightweight collection of key-value pairs.

当您需要有序键值对集合并且不需要快速键查找时

when you need an ordered collection of key-value pairs and don’t require the fast key lookup

let recordTimes: KeyValuePairs = ["Florence Griffith-Joyner": 10.49,
                                      "Evelyn Ashford": 10.76,
                                      "Evelyn Ashford": 10.79,
                                      "Marlies Gohr": 10.81]
print(recordTimes.first!)
// Prints "("Florence Griffith-Joyner", 10.49)"

引用： KeyValuePairs

但是，如果您想以其他方式解决它，我建议使用 Array 。要获取键值，可以将其存储在 Tuple 中。假设数组元组。请看下面的示例：

However, If you want to solve it different way I would recommend Array. To have a key, value in collection you can store it in Tuple. Let say array of tuples. Take a look on example below:

let inputDataSet: [(String, Any)] = [("id",1), ("name","Thomas"), ("role","Programming Geek"), ("header","bla"), ("dept","nloo"), ("address","dsd"), ("pic","asd")]

for (key, value) in inputDataSet {
    print("current key:\(key) value:\(value)")
}

上面的狙击结果如下所示：

Result of the sniper above is as presented below:

current key:id value:1
current key:name value:Thomas
current key:role value:Programming Geek
current key:header value:bla
current key:dept value:nloo
current key:address value:dsd
current key:pic value:asd

为此，您有了订单和键值对象。
希望对您有所帮助！

Thanks to this you have an order and key, value object. Hope it helps!

更新：

答案已更新以反映更改。

Answer was updated to reflect changes.

将DictionaryLiteral类型重命名为KeyValuePairs

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