比较XML代码段？ [英] Compare XML snippets?

问题描述

以另一个SO问题为基础，如何检查两个格式正确的XML代码段在语义上是相等的。我需要的只是是否等于，因为我正在将其用于单元测试。

在我想要的系统中，这些值相等（请注意顺序） '开始'
和'结束'）：

 <？xml version ='1.0'encoding ='utf -8'standalone ='是'？> 
< Stats start = 1275955200 end = 1276041599> 
< / Stats> 
 
＃重新排序了开始和结束
 
<？xml version ='1.0'encoding ='utf-8'standalone ='yes'？> 
< Stats end = 1276041599 start = 1275955200> 
< / Stats> 
  

我可以使用lmxl和其他工具，而一个简单的函数仅允许对属性进行重新排序工作也很好！

---

基于IanB答案的工作段：

  from formencode.doctest_xml_compare import xml_compare 
＃必须剥离这些或fromstring鲤鱼
 xml1 =<？xml version ='1.0'encoding ='utf-8' standalone ='yes'？> 
< Stats start = 1275955200 end = 1276041599< / Stats> 
 xml2 =<？xml version = '1.0'encoding ='utf-8'standalone ='是'？> 
< Stats end = 1276041599 start = 1275955200>< / Stats> 
 xml3 =<？xml version ='1.0'encoding ='utf-8'standalone ='yes'？> 
< Stats start = 1275955200>< / Stats>来自lxml的
 
导入etree 
 tree1 = etree.fromstring（xml1.strip（））
 tree2 = etree.fromstring（xml2.strip（））
 tree3 = etree.fromstring（xml3.strip（））
 
导入系统
记者= lambda x：sys.stdout.write（x + \n）
 
断言xml_compare（tree1，tree2，reporter）
断言xml_compare（tree1，tree3，reporter）为F其他
  

解决方案

您可以使用 formencode.doctest_xml_compare － xmlTree或Trees比较两个元素。 p>

Building on another SO question, how can one check whether two well-formed XML snippets are semantically equal. All I need is "equal" or not, since I'm using this for unit tests.

In the system I want, these would be equal (note the order of 'start' and 'end'):

<?xml version='1.0' encoding='utf-8' standalone='yes'?>
<Stats start="1275955200" end="1276041599">
</Stats>

# Reordered start and end

<?xml version='1.0' encoding='utf-8' standalone='yes'?>
<Stats end="1276041599" start="1275955200" >
</Stats>

I have lmxl and other tools at my disposal, and a simple function that only allows reordering of attributes would work fine as well!

---

Working snippet based on IanB's answer:

from formencode.doctest_xml_compare import xml_compare
# have to strip these or fromstring carps
xml1 = """    <?xml version='1.0' encoding='utf-8' standalone='yes'?>
    <Stats start="1275955200" end="1276041599"></Stats>"""
xml2 = """     <?xml version='1.0' encoding='utf-8' standalone='yes'?>
    <Stats end="1276041599" start="1275955200"></Stats>"""
xml3 = """ <?xml version='1.0' encoding='utf-8' standalone='yes'?>
    <Stats start="1275955200"></Stats>"""

from lxml import etree
tree1 = etree.fromstring(xml1.strip())
tree2 = etree.fromstring(xml2.strip())
tree3 = etree.fromstring(xml3.strip())

import sys
reporter = lambda x: sys.stdout.write(x + "\n")

assert xml_compare(tree1,tree2,reporter)
assert xml_compare(tree1,tree3,reporter) is False

解决方案

You can use formencode.doctest_xml_compare -- the xml_compare function compares two ElementTree or lxml trees.

这篇关于比较XML代码段？的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！