D3D11：从6张图像创建一个立方体贴图 [英] D3D11: Creating a cube map from 6 images

问题描述

如何在D3D11中从6张图像创建立方体贴图？我发现的所有示例仅使用一个.dds。具体来说，如何上传立方体纹理的各个面？

How do I create a cube map in D3D11 from 6 images? All the examples I've found use only one .dds. Specifically, how do I upload individual faces of the cube texture?

推荐答案

它的工作原理如下：

D3D11_TEXTURE2D_DESC texDesc;
texDesc.Width = description.width;
texDesc.Height = description.height;
texDesc.MipLevels = 1;
texDesc.ArraySize = 6;
texDesc.Format = DXGI_FORMAT_R8G8B8A8_UNORM;
texDesc.CPUAccessFlags = 0;
texDesc.SampleDesc.Count = 1;
texDesc.SampleDesc.Quality = 0;
texDesc.Usage = D3D11_USAGE_DEFAULT;
texDesc.BindFlags = D3D11_BIND_SHADER_RESOURCE;
texDesc.CPUAccessFlags = 0;
texDesc.MiscFlags = D3D11_RESOURCE_MISC_TEXTURECUBE;

D3D11_SHADER_RESOURCE_VIEW_DESC SMViewDesc;
SMViewDesc.Format = texDesc.Format;
SMViewDesc.ViewDimension = D3D11_SRV_DIMENSION_TEXTURECUBE;
SMViewDesc.TextureCube.MipLevels =  texDesc.MipLevels;
SMViewDesc.TextureCube.MostDetailedMip = 0;

D3D11_SUBRESOURCE_DATA pData[6];
std::vector<vector4b> d[6]; // 6 images of type vector4b = 4 * unsigned char

for (int cubeMapFaceIndex = 0; cubeMapFaceIndex < 6; cubeMapFaceIndex++)
{   
    d[cubeMapFaceIndex].resize(description.width * description.height);

    // fill with red color  
    std::fill(
        d[cubeMapFaceIndex].begin(), 
        d[cubeMapFaceIndex].end(), 
        vector4b(255,0,0,255));

    pData[cubeMapFaceIndex].pSysMem = &d[cubeMapFaceIndex][0];// description.data;
    pData[cubeMapFaceIndex].SysMemPitch = description.width * 4;
    pData[cubeMapFaceIndex].SysMemSlicePitch = 0;
}

HRESULT hr = renderer->getDevice()->CreateTexture2D(&texDesc, 
    description.data[0] ? &pData[0] : nullptr, &m_pCubeTexture);
assert(hr == S_OK);

hr = renderer->getDevice()->CreateShaderResourceView(
    m_pCubeTexture, &SMViewDesc, &m_pShaderResourceView);
assert(hr == S_OK);

这将为CubeMap创建六个红色图像。

This creates six "red" images, for the CubeMap.

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