如何在Django模板中使用href属性 [英] how to use the href attribute in django templates

问题描述

当我尝试使用Django模板中的链接时，从 / appname / index / 转到 / appname / detail / ### 我改为访问 / appname / index / detail / ### ，这不是我要获取的内容，因此我的应用可以当然不能在urlconf中找到它。

When I try to use a link in my Django template from /appname/index/ to get to /appname/detail/### I am instead getting to /appname/index/detail/### which is not what I'm trying to get so my app can't find it in the urlconf of course.

首先是详细信息页面的urls.py行

First the urls.py line for the detail page

url(r'detail/(?P<jobID>\d+)/$', 'appname.views.detail')

另外，根urlconf

Additionally, the root urlconf

urlpatterns = patterns('', 
    url(r'^appname/', include('appname.urls')),
    url(r'^admin/', include(admin.site.urls)),
)

接下来尝试到达的模板代码

Next the template code trying to get there

{% for job in jobList %}
    <a href="detail/{{ job.id }}/">{{ job.name }}</a>

我不确定还有什么适用的信息，只问您是否想看看其他。我也尝试过：

I'm not sure what else might be applicable information, just ask if you would like to see something else. I also tried :

<a href="{% url 'appname.views.detail' %}/{{ job.id }}">{{ job.name }}</a>

但这都不起作用。预先感谢您的帮助。

But that didn't work either. Thank you in advance for any help.

推荐答案

在开始时添加 / 在 href 中：

<a href="/appname/detail/{{ job.id }}/">{{ job.name }}</a>

并使用 url 标记为您工作需要这样做：

And for the url tag to work you need to do it like this:

<a href="{% url 'appname.views.detail' jobID=job.id %}">{{ job.name }}</a>

这篇关于如何在Django模板中使用href属性的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！