我怎样才能从NG-资源的网址？ [英] How can I get the url from an ng-resource?

问题描述

我怎样才能从NG-资源的URL（而params）？

How can I get the url (and params) from an ng-resource?

如果我怎样才能创建一个包装或延长NG-资源，所以我得到这个功能？这是不可能的。

And if that is not possible how can I create a wrapper or extend ng-resource so I get this functionality?

更新：我希望能够提取资源对象的URL，而params而没有发送请求。

Update: I want to be able to extract the URL and params from the resource object without ever sending a request.

在一个理想的世界了以下工作：

In an ideal world the following works:

myResource = $resource('localhost/foo/bar');

myResource.getUrl() // returns localhost/foo/bar

由于使用getURL功能不存在我想我在<一个发现了以下href=\"http://stackoverflow.com/a/28474289/4829972\">http://stackoverflow.com/a/28474289/4829972

一个包装厂：

angular.module('app').factory('ExtendedResourceFactory',['$resource',
  function($resource) {
    function ExtendedResourceFactory() {
      var Resource = $resource.apply(this, arguments);

      Resource.prototype.getArguments = function() {
        return arguments
      };

      return Resource;
    }

    return ExtendedResourceFactory;
  }
]); 

我注入了新的工厂，并尝试一下：

I inject the new factory and try it out:

res = ExtendedResourceFactory('url')
res.getArguments()

Uncaught TypeError: res.getArguments is not a function(…) 

感恩路或解决方案!!

Thankful for directions or solutions!!

推荐答案

也许下面将使用。既然你的URL的显式控制被传递到$资源，我想你可以改变的响应，提供你想要的功能。它绝不是干净的，但确实出现功能

Maybe the following will be of use. Since you have explicit control of the URL being passed into $resource, I assume you can transform the response to provide the function you desire. It is by no means clean, but does appear functional.

var resource;

resource = $resource('/foo/bar', 
  {
    id: 1
  }, {
    get: {
      method: 'GET',
      transformResponse: function(data) {
        data = angular.fromJson(data);
        data.getUrl = function() {
          return '/foo/bar';
        };
        return data;
      }
    }
  }
);

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