django-filter页面启动时结果列表为空 [英] Empty result list on django-filter page startup

问题描述

我正在使用

解决方案

之后一些研究，我发现了这个简单的解决方案

  class ProductFilter（django_filters.FilterSet）：
 class Meta：
模型=产品
字段= ['短名称'，'全名'，'描述'，'产品类型'，] 
 
 def __init __（self，* args，** kwargs）：
 super（ProductFilter，self ）.__ init __（* args，** kwargs）
＃在sturtup用户处不按Submit按钮，如果self.data == {}：$ b $，则QueryDict（数据中）为空
 b self.queryset = self.queryset.none（）
  

我认为，这种解决方案是稳定的。您如何看待？

I'm using https://github.com/alex/django-filter

When user opens the page with filter at the first time, they see the empty form and full list of results.

I need to not to display the result until user press Search for a first time.

In other words - django-filter should not display any results if parameters list (in url) is empty, and display all results if parameter values (in url) is empty.

Source

filters.py

import django_filters

from product.models import Product

class ProductFilter(django_filters.FilterSet):

    class Meta:
        model = Product
        fields = [ 'shortname', 'fullname', 'description', 'product_type' ]

views.py

from product.filters import ProductFilter

def product_search_in_ancestors(request, product_id):
    context = RequestContext(request)    
    p = get_object_or_404( Product, pk=product_id )

    q = Product.objects.filter( id__in = p.GetChilds() )

    filter = ProductFilter(request.GET , queryset=q )

    return render_to_response( 'product/product_search_in_ancestors.html',
        {'product':p,
        'filter': filter
         },
         context)

Link to same issue on github

解决方案

After some studies, I've found this simple solution

class ProductFilter(django_filters.FilterSet):
    class Meta:
        model = Product
        fields = [ 'shortname', 'fullname', 'description', 'product_type',   ]

    def __init__(self, *args, **kwargs):
        super(ProductFilter, self).__init__(*args, **kwargs)
        # at sturtup user doen't push Submit button, and QueryDict (in data) is empty
        if self.data == {}:
            self.queryset = self.queryset.none()

I think, this solution is stable. How do you think?

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