将ZipFile对象存储到Django数据库中 [英] Storing ZipFile Objects into the Django database

问题描述

我认为我遇到的问题非常罕见，因为我似乎无法在此处或在Google上找到答案。

我在数据库中按顺序存储了几张图片为了提供这些服务，我想压缩它们，将创建的ZipFile存储在数据库中，该数据库具有AmazonS3存储作为后端。更重要的是，所有这些操作都是在Celery管理的后台任务中完成的。现在...这是我编写的代码：

The problem I have is quite uncommon I think, because I didn't seem to be able to find an answer on here or on Google.
I have several pictures stored in my database and in order to serve these, I want to zip them, store the ZipFile created in the database which has an AmazonS3 storage as a backend. On more thing, all these operations are done in a background task managed by Celery. Now... Here is the code I wrote :

zipname = "{}.zip".format(reporting.title)

with ZipFile(zipname, 'w') as zf:
    # Here is the zipfile generation. It quite doesn't matter anyway since this works fine.
    reporting = Reporting.objects.get(pk=reporting_id)
    reporting.pictures_archive = zf
    reporting.save()

我得到了错误： *** AttributeError：'ZipFile'对象没有属性'_committed'

因此，我尝试通过以下方式将zipfile转换为Django文件： zf = File（zf），但它返回一个空对象。

I got the error : *** AttributeError: 'ZipFile' object has no attribute '_committed'
So I tried to cast the zipfile into a Django File this way : zf = File(zf) but it returns an empty object.

有人可以帮我吗？我有点被困住了……

Can anyone help me with that ? I'm kind of stuck...

推荐答案

这有点不像我想的那么复杂。 （我想这可以解释为什么没有人在整个互联网上都问这个问题）。

使用Python 3.3，您的字符串是unicode，而您主要使用unicode对象。文件需要字节数据才能正常工作，因此以下是解决方法：

This was kind of not as complicated as I thought. (Which could explain why no one asked that question all over the internet I guess)
Using Python 3.3, your strings are unicode and you mainly work with unicode objects. File needs bytes data to work correctly so here is the solution :

zipname = "{}.zip".format(reporting.id, reporting.title)

with ZipFile(zipname, 'w') as zf:
    # Generating the ZIP ! 

reporting = Reporting.objects.get(pk=reporting_id)
reporting.pictures_archive.delete()
reporting.pictures_archive = File(open(zipname, "rb"))
reporting.save()

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