MultiValueDictKeyError / request.POST [英] MultiValueDictKeyError / request.POST
问题描述
我认为我在 request.POST ['title']
MultiValueDictKeyError在/博客/添加/帖子/
标题
请求方法:GET
请求网址: http://119.81.247.69:8000/blog/add/post/
Django版本:1.8.2
异常类型:MultiValueDictKeyError
异常值:
'title'
异常位置: getitem <中的/usr/local/lib/python2.7/dist-packages/django/utils/datastructures.py / strong>,第322行
Python可执行文件:/ usr / bin / python
Python版本:2.7.3
MultiValueDictKeyError at /blog/add/post/ "'title'" Request Method: GET Request URL: http://119.81.247.69:8000/blog/add/post/ Django Version: 1.8.2 Exception Type: MultiValueDictKeyError Exception Value:
"'title'" Exception Location: /usr/local/lib/python2.7/dist- packages/django/utils/datastructures.py in getitem, line 322 Python Executable: /usr/bin/python Python Version: 2.7.3
views.py
def add_post(request):
entry_title = request.POST["title"]
return HttpResponse('Hello %s' % entry_title)
write.html
<form method="POST" action="/blog/add/post/">
<p>
<label for "title">Title</label>
<input type="text" id="title" name="title" value="" />
</p>
<p>
<label for 'category'>Category</label>
<select id="category" name="category"></select>
</p>
<p>
<label for 'tags'>Tags</label>
<input type="text" id="tags" value="" />
</p>
<p>
<textarea id="content" name="content"></textarea>
</p>
<p>
<input type="submit" value="Write" />
</p>
推荐答案
更改:
def add_post(request):
entry_title = request.POST["title"]
return HttpResponse('Hello %s' % entry_title)
至:
def add_post(request):
entry_title = request.POST.get("title", "Guest (or whatever)")
return HttpResponse('Hello %s' % entry_title)
并且不会抛出 KeyError
,但是您应该考虑使用Django的表单,而不是直接从POST数据中提取值。
and it won't throw a KeyError
, but you should look at using Django's forms rather than pulling values directly from the POST data.
,您可以保留现有代码,只需检查异常即可:
Alternatively, you can keep your existing code and simply check for the exception:
def add_post(request):
try:
entry_title = request.POST["title"]
except KeyError:
entry_title = "Guest"
return HttpResponse('Hello %s' % entry_title)
但是这就是 .get()
在内部已经完成的工作。
but this is what .get()
does internally already.
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