Django-在“详细信息”中获取错误“反向”，但未找到参数。尝试了1个模式：“当使用{％url“ music：fav” ％} [英] Django - getting Error "Reverse for 'detail' with no arguments not found. 1 pattern(s) tried:" when using {% url "music:fav" %}

问题描述

我正在学习最近4天的django框架。
今天，我试图通过使用

I am learning django framework from last 4 days. Today I was trying to retrieve a URL in HTML template by using

{％url music：fav％}

{% url "music:fav" %}

我在music / urls.py中将命名空间设置为

where I set the namespace in music/urls.py as

app_name = music

app_name= "music"

，还有一个名为fav（）的函数。
这是代码：

and also I have a function named fav(). Here is the codes:

music / urls.py

music/urls.py

from django.urls import path
from . import views
app_name = 'music'

urlpatterns = [
path("", views.index, name="index"),
path("<album_id>/", views.detail, name="detail"),
path("<album_id>/fav/", views.fav, name="fav"),
]

music / views.py

music/views.py

def fav(request):
    song = Song.objects.get(id=1)
    song.is_favorite = True
    return render(request, "detail.html")

detail.html我用过

in detail.html I used

{% url 'music:fav' %}

但是我不知道为什么会显示此错误：

But I dont know why this is showing this error:

在/ music / 1 /上的NoReverseMatch反转'detail'，不带参数，不找到
。尝试了1种模式：['music\ /（？P [^ /] +）\ / $']

NoReverseMatch at /music/1/ Reverse for 'detail' with no arguments not found. 1 pattern(s) tried: ['music\/(?P[^/]+)\/$']

推荐答案

path("<album_id>/fav/", views.fav, name="fav"),

此URL需要 album_id 。像这样的东西：

This URL needs the album_id. Something like this:

{% url 'music:fav' 1 %}
{% url 'music:fav' album.id %}

这篇关于Django-在“详细信息”中获取错误“反向”，但未找到参数。尝试了1个模式：“当使用{％url“ music：fav” ％}的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！