如何在Django 1.7中的表单模型中获取当前登录的用户ID？ [英] How to get currently logged user id in form model in Django 1.7?

问题描述

假设我有一个显示歌曲的网页。假设有公开和私人歌曲。公开歌曲可供所有人查看，而私人歌曲是特定用户创建的歌曲，并且仅供他查看。因此，用户只能看到owner_id == NULL和owner_id == current_logged_in_user_id（自己的ID）的歌曲

型号：

  import .... 
 
 class Song（models.Model）：
 name = models.CharField（max_length = 100） 
持续时间= models.IntegerField（max_length = 15）
 owner = models.ForeignKey（settings.AUTH_USER_MODEL，null = True，blank = True）
 
 def __unicode __（self）： 
 return self.name 
  

视图：

django.shortcuts中的

 导入渲染，重定向，get_object_or_404 
 django.contrib.auth.decorators导入login_required 
从songapp.models导入Song 
从songapp.forms导入SongInfoForm 
 
 @login_required 
 def song_info（request）：
 song = get_object_or_404（Box）
 song_status = song.get_status（）
 form = SongInfoForm（initial = {'song_list'：song.song_list}）
 
 return render（request，'songapp / song_info.html'，
 {'form'：form，'song'：song，'song_status'：song_status}）
   
 
 
表格：
 从django导入表格
从django.forms导入ModelChoiceField 
 
从songapp.models导入Song 
 
 
类SongInfoForm（forms.Form）：
 
- > selected_songs = Song.objects.filter（owner = None）| Song.objects.filter（owner = 3）
 song_list = ModelChoiceField（queryset = selected_songs，required = False）
  
请注意Form文件中带有箭头的行。这就是问题所在。该代码现在可以使用，但是
 
 
（所有者= 3）
 
 
是硬编码的。我知道我的用户ID是3。但是我希望它能正常工作。应该是这样的：
 
 
（owner = current_logged_in_user.id）
 
 
我对Django和Python还是很陌生，我不知道如何将用户ID传递给SongInfoForm FormModel。
解决方案
我已经解决了。
 
 
 
在views.py中进行更改：
  form = SongInfoForm（initial = {'song_list'：song.song_list}，user = request.user）
  
感谢之前的回答和本示例
  
我已经想到了这一点，并且
 
 
 
在forms.py 
  class SongInfoForm（forms.Form）：
 def __init __（self，* args，** kwargs）：
 user = kwargs.pop（'user'）
 super （SongInfoForm自身）。__init __（* args，** kwargs）
 self.fields [’song_list’] = form.ModelChoiceField（queryset = Song.objects.filter（owner = None）| Song.playlist.objects.filter（owner = user），required = False）
  
 
Let's say I have a webpage that displays songs. And let's say there are public and private songs. Public songs are available for everyone to see, while private songs are songs that a certain user has created and are only available for him to see. So the user should only see those songs with the owner_id == NULL and owner_id == currently_logged_in_user_id (his own id)

Model:
import ....

    class Song(models.Model):
        name = models.CharField(max_length=100)    
        duration = models.IntegerField(max_length=15)
        owner = models.ForeignKey(settings.AUTH_USER_MODEL, null=True, blank=True)

        def __unicode__(self):
            return self.name
View:
from django.shortcuts import render, redirect, get_object_or_404
from django.contrib.auth.decorators import login_required
from songapp.models import Song
from songapp.forms import SongInfoForm

@login_required
def song_info(request):
    song = get_object_or_404(Box)
    song_status = song.get_status()
    form = SongInfoForm(initial={'song_list': song.song_list})

    return render(request, 'songapp/song_info.html',
        {'form': form, 'song': song, 'song_status': song_status})
Form:
    from django import forms
    from django.forms import ModelChoiceField

    from songapp.models import Song


    class SongInfoForm(forms.Form):

-->     selected_songs = Song.objects.filter(owner=None) | Song.objects.filter(owner=3)
        song_list = ModelChoiceField(queryset=selected_songs, required=False)
Note the line with the arrow in the Form file. This is where the problem lies. The code works now, but the 

  
(owner = 3)
is hardcoded. I know for a fact that my users id is 3. But I want it to work properly. It should be something like this:

  
(owner = currently_logged_in_user.id)
I'm still very new to Django and Python and I don't know how to pass the users id to the SongInfoForm FormModel.
解决方案
I've figured it out.

In views.py change:
form = SongInfoForm(initial={'song_list': song.song_list}, user=request.user)
And thanks to the answers before and this example
django form: Passing parameter from view.py to forms gives out error
I've came up with this, and it works like a charm.

In forms.py
class SongInfoForm(forms.Form):
    def __init__(self, *args, **kwargs):
        user = kwargs.pop('user')
        super(SongInfoForm, self).__init__(*args, **kwargs)
        self.fields['song_list'] = forms.ModelChoiceField(queryset=Song.objects.filter(owner=None) | Song.playlist.objects.filter(owner=user), required=False)


                        
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