基于计算值的Django计算 [英] Django calculation based on calculated value

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问题描述

我再次需要您的帮助。我正在为我的作战小组进行一个项目。这是一个简单的排名网站。所以我们有球员,他们参加比赛并获得积分。现在我可以分配球员参加锦标赛,分配他们在比赛中所占的席位了。

I need your help once more. I am working on a project for my wargaming group. It is a simple ranking site. So we have players, they participate in tournaments and get points. I got to the point where I am able to assign players to tournaments, assign place they took at the tournament to their name.

现在我必须计算积分。算法很简单,但是我很难将值从锦标赛模型传递到排名。每个锦标赛都有一个计算得出的评分(基于其他因素,主要是更大的锦标赛,更大的评分),在其他模型中,我无法使用它,需要您的帮助。最重要的是,如果在锦标赛中更改评级值会强制更新所有相关计算,那将是非常棒的。

Now I have to calculate points. Algorithm is simple, but I have problems passing a value from Tournament model to Ranking. Each Tournament has a calculated rating (based on other things, mostly bigger tournament, bigger rating) and in other models, I was unable to use it and need your help with it. On top of that, it would be awesome if changing a rating value in Tournament would force an update of all dependent calculations.

所以我们有这样的模型:

So we have models like that:

 class Player(models.Model):
    class Meta:
    name = models.CharField(max_length=50)
    nicname = models.CharField(max_length=50,blank=True)
    army = models.CharField(max_length=50)
    def __unicode__(self):
        return self.name
    def __str__(self):
        return self.name

class Tournament(models.Model):
    class Meta:
    name = models.CharField(max_length=100)
    date = models.DateTimeField('date')
    player_num = models.IntegerField
    points = models.FloatField(default=1000.00)


    def __unicode__(self):
        return self.name
    def __str__(self):
        return self.name

然后我有这种排名模型:

And then I have a ranking model of this kind:

class TournamentStandings(models.Model):
    tournament = models.ForeignKey(Tournament, on_delete=models.CASCADE)
    player = models.ForeignKey(Player, on_delete=models.CASCADE)
    player_place = models.FloatField

在admin.py中,我对TournamentAdmin进行计算:

In admin.py I do calculations for TournamentAdmin:

fields = ['name', 'date', 'player_num', 'points', 'get_rating']
def get_rating(self, obj):
    return obj.points / 100.00

现在我想对TournamentStandingsAdmin进行计算:

And now I would like to make calculation for TournamentStandingsAdmin:

def player_points(self, obj):
    return (obj.tournament.player_num/obj.player_place)* obj.tournament.get_rating

但是结果是错误


'Tournament'对象没有属性'get_rating'

'Tournament' object has no attribute 'get_rating'

所以我的猜测是我计算出的 get_rating 不是真实的模型字段,但是如何解决呢?

So my guess is my calculated get_rating is not a true model field but how to work around that?

推荐答案

如@Daniel所建议的,您需要在您的计算机上添加 get_rating 方法锦标赛模型。

as @Daniel suggested you need to add get_rating method to your Tournament model.

class Tournament(models.Model):
    name = models.CharField(max_length=100)
    date = models.DateTimeField('date')
    player_num = models.IntegerField
    points = models.FloatField(default=1000.00)

    ....
    def get_rating(self):
        return obj.points / 100.00

之后,您可以使用 Tournament 对象调用该方法,如下所示:

After that you can call the method with a Tournament object as follows:

obj.tournament.get_rating

这篇关于基于计算值的Django计算的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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