在Python中检测装饰器 [英] Detect Decorator in Python

问题描述

在python中，是否可以检测到另一个函数上是否存在装饰器？

In python, is it possible to detect if there is a decorator on another function?

具体来说，我正在尝试（在django中）编写一些中间件将检测正在处理的视图是否已包装在@login_required装饰器中。

Specifically, I'm trying (in django) to write some middleware that will detect if the view being processed has been wrapped in the @login_required decorator.

class SomeMiddleware(object):

    def process_view(self, request, view_func, view_args, view_kwargs):
        if has_decorator(view_func):
            print "this view was decorated"

我要填写的是 has_decorator部分...。

What I'm trying to fill in is the "has_decorator" portion....

这可能吗？

推荐答案

在外壳中快速浏览一下即可显示 func_closure 函数的属性在未修饰的函数中为空，但在修饰的函数中包含数据。并非总是100％地确定这是真的，但这也许对您有用。

Just some quick fooling around in the shell shows that the func_closure attribute on a function is empty on undecorated functions, but contains data in decorated functions. Not 100% sure this is true all the time, but maybe this works out for you.

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