doctrine dbal每组获取最新的聊天消息 [英] doctrine dbal get latest chat message per group

问题描述

在尝试进行多项选择时

$result = $this->qb->select('c.id','c.message','acc.name as chat_from', 'c.chat_to as count')
    ->addSelect("SELECT * FROM chat ORDER BY date_deliver DESC")
        ->from($this->table,'c')
        ->join('c','account','acc', 'c.chat_from = acc.id')
        ->orderBy('date_sent','DESC')
        ->groupby('chat_from')
        ->where('chat_to ='.$id)
        ->execute();
        return $result->fetchAll();

我也尝试过

$result = $this->qb->select('c.id','c.message','acc.name as chat_from', 'c.chat_to as count')
        ->from("SELECT * FROM chat ORDER BY date_deliver DESC",'c')
        ->join('c','account','acc', 'c.chat_from = acc.id')
        ->orderBy('date_sent','DESC')
        ->groupby('chat_from')
        ->where('chat_to ='.$id)
        ->execute();
        return $result->fetchAll();

我想按分组依据显示数据，然后在最后一个条目内显示数据。

I want to display the data by group by and then display the data inside the last entry.

我用过DOCTRINE DBAL

i' used DOCTRINE DBAL

请帮助我

推荐答案

由于您的问题不清楚，所以我假设您需要获取每个组的最近聊天/消息，对此的等效SQL将是

As your question is unclear so i am assuming you need to get the recent chat/message per group, the equivalent SQL for this will be

 SELECT c.id, c.message, a.name as chat_from, c.chat_to as count
 FROM account a
 JOIN chat c ON(c.chat_from = a.id )
 LEFT JOIN chat cc ON(c.chat_from = cc.chat_from AND c.date_sent < cc.date_sent)
 WHERE cc.date_sent IS NULL AND c.chat_to = @id
 ORDER BY c.date_sent DESC

因此，使用doctrine dbal可以在上面的查询中编写

So using doctrine dbal you can write above query as

$this->qb->select( 'c.id', 'c.message', 'a.name as chat_from', 'c.chat_to as count' )
         ->from( 'account', 'a' )
         ->join( 'a', 'chat', 'c', 'c.chat_from = a.id' )
         ->leftJoin( 'c', 'chat', 'cc', 'c.chat_from = cc.chat_from AND c.date_sent < cc.date_sent' )
         ->where( 'cc.date_sent IS NULL' )
         ->andWhere( 'c.chat_to =' . $id )
         ->orderBy( 'c.date_sent', 'DESC' )
         ->execute();

再次不查看示例数据和DDL，这不是一个完整的解决方案。

Again without viewing the sample data and DDL its not a complete solution.

参考

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