如何将十六进制字符串转换为双精度？ [英] How to convert an hexadecimal string to a double?

问题描述

我从BLE到我的手机a的范围为0x0000到0x01c2的十六进制值是 String 。为了将其绘制在图形中，我必须将其转换为 double ，为此我尝试了此方法，但不幸的是，它对我而言无济于事。

I'm getting the hexadecimal values of range 0x0000 to 0x01c2 from BLE to my phone a as String. In order to plot it in a graph, I have to convert it into double, for which I've tried this method but sadly it couldn't help in my case.

以下是提供的链接中经过少许修改的代码：

Here is the little modified code from the provided link:

String receivedData = CommonSingleton.getInstance().mMipsData; // 0x009a
long longHex = parseUnsignedHex(receivedData);
double d = Double.longBitsToDouble(longHex);

public static long parseUnsignedHex(String text) {
    if (text.length() == 16) {
        return (parseUnsignedHex(text.substring(0, 1)) << 60)
                | parseUnsignedHex(text.substring(1));
    }
    return Long.parseLong(text, 16);
}

任何进一步的帮助将不胜感激。

Any further help would be much appreciated. Thanks in advance.

推荐答案

您的值不是IEEE-754浮点值的十六进制表示-只是整数。因此，在删除开头的 0x前缀之后，只需将其解析为整数即可：

Your value isn't a hex representation of an IEEE-754 floating point value - it's just an integer. So just parse it as an integer, after removing the leading "0x" prefix:

public class Test {
    public static void main(String[] args) {
        String text = "0x009a";

        // Remove the leading "0x". You may want to add validation
        // that the string really does start with 0x
        String textWithoutPrefix = text.substring(2);
        short value = Short.parseShort(textWithoutPrefix, 16);
        System.out.println(value);
    }
}

如果您确实需要 double 在其他地方，您可以隐式转换：

If you really need a double elsewhere, you can just implicitly convert:

short value = ...;
double valueAsDouble = value;

...但是除非您确实需要，否则我会尽量避免这样做。

... but I'd try to avoid doing so unless you really need to.

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