elementtree注册名称空间错误 [英] elementtree register namespace error
问题描述
我尝试使用以下方法注册名称空间:
I tried to register namespace with this:
ET.register_namespace("inv", "http://www.stormware.cz/schema/version_2/invoice.xsd")
但它不起作用:
Traceback (most recent call last):
File "C:\tutorial\temp_xml2.py", line 34, in module>
for listInvoice in root.findall('inv:invoiceHeader'):
File "C:\Python27\LIB\xml\etree\ElementTree.py", line 390, in findall
return ElementPath.findall(self, path, namespaces)
File "C:\Python27\LIB\xml\etree\ElementPath.py", line 293, in findall
return list(iterfind(elem, path, namespaces))
File "C:\Python27\LIB\xml\etree\ElementPath.py", line 259, in iterfind
token = next()
File "C:\Python27\LIB\xml\etree\ElementPath.py", line 83, in xpath_tokenizer
raise SyntaxError("prefix %r not found in prefix map" % prefix)
SyntaxError: prefix 'inv' not found in prefix map
>>>
这怎么了?
感谢Martinj
我尝试-1。:
for listInvoice in root.findall('inv:invoiceHeader', namespaces=dict(inv='http://www.stormware.cz/schema/version_2/invoice.xsd')):
invoiceHeader = listInvoice.find('inv:id', namespaces=dict(inv='http://www.stormware.cz/schema/version_2/invoice.xsd')).text
print invoiceHeader
结果:(空)
2。 :
nsmap=root.nsmap
print nsmap
结果:AttributeError:'Element'对象没有属性'nsmap'
Result: AttributeError: 'Element' object has no attribute 'nsmap'
3 .:
for listInvoice in root.findall('.//{http://www.stormware.cz/schema/version_2/invoice.xsd}invoiceHeader'):
invoiceHeader = listInvoice.find('.//{http://www.stormware.cz/schema/version_2/invoice.xsd}id').text
print invoiceHeader
结果:可以。
是否有机会一次注册名称空间?然后,我想使用listInvoice.find('inv:id')。text代替listInvoice.find('.// {http://www.stormware.cz/schema/version_2/invoice.xsd} id') .text(更清晰,更易于阅读的代码)
Is there any chance to register namespaces at once? Then I would like to use listInvoice.find('inv:id').text instead of listInvoice.find('.//{http://www.stormware.cz/schema/version_2/invoice.xsd}id').text (nicer code and easy to read)
推荐答案
看来该文档尚未更新如何使用名称空间和 .findall()
。
It looks like the documentation hasn't been updated on how to use namespaces and .findall()
.
.findall()
函数(以及 .find()
, .findtext()和
.iterfind())接受一个
namespaces`参数成为一个映射。这是查找标记时查询的唯一结构:
The .findall()
function (as well as .find()
, .findtext() and
.iterfind()) takes a
namespaces` argument which is supposed to be a mapping. That is the only structure consulted when finding tags:
root.findall('inv:invoiceHeader', namespaces=dict(inv='http://www.stormware.cz/schema/version_2/invoice.xsd'))
.register_namespace()
函数仅在将树再次序列化为文本时有用。
The .register_namespace()
function is only useful for when serializing a tree out to text again.
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